The complete question is
John and Matt are going to fill a pool with 2 different sized hoses. John can fill the pool in 5 hours, while Matt can complete it in 10 hours.How long will it take both to fill the pool? Explain each step in solving this equation.
we know that
<span>John can fill the pool in --------------> 5 hours
</span>therefore
<span>I calculate the amount of pool that John fills in one hour
</span>if John can fill 100% of the pool in----------------> 5 hours
X--------------------------------------> 1 hour
X=1/5=0.20 pool/hour
Matt can fill the pool in --------------> 10 hours
therefore
I calculate the amount of pool that Matt fills in one hour
if Matt can fill 100% of the pool in----------------> 10 hours
X--------------------------------------> 1 hour
X=1/10=0.10 pool/hour
<span>adding both amounts
(0.20+0.10)=0.30 -----------> 30% pool/hour
then
</span>if both can fills 30% of the pool in----------------> 1 hour
100%-------------------------------> X
X=100/30=3.33 hours----------> 3 hours + 19 minutes+ 48 sec
the answer is 3.33 hours (3 hours + 19 minutes+ 48 sec)
<span>The equation to determine the amount of pool filling (y) according to time (t) in hours is given by
</span><span>y=0.30*t
</span>
<span>△XLW≅△XDG
GX = WX = 5.7
hope it helps</span>
Answer:
y = -x - 3
Step-by-step explanation:
Sorry it’s late but hope this helps. Pls give brainliest.
Answer:
x = 
Step-by-step explanation:
Data provided:
ln(x) − ln(y) = 2a
Now,
The using the following properties of log function,
we have
log(A) - log(B) = 
and,
ln(a) = b is equivalent to a = 
(here e is exponential )
ln(e) = 1
therefore,
the above equation transforms as:
= 2a
taking anti-ln both sides,
we get
= 
or
x =
