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oksian1 [2.3K]
3 years ago
10

Find the LCM and HCF of 110 and 220 by prime factorization what do you observe....pls answer this ​

Mathematics
1 answer:
ElenaW [278]3 years ago
8 0

Answer: Check if numbers are prime. Composite numbers prime factorization (decomposing, breaking numbers down to prime factors). Inscribe them as a product of prime factors, in exponential notation.

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dmitriy555 [2]

Answer: The attachment is blank

Step-by-step explanation: :/

5 0
3 years ago
What is the value of f if f + I-3 11/12 = 18
astra-53 [7]
Solve for f:(i - 47/12) + f = 18
(i - 47/12) + f = f + (-47/12 + i):
f + (-47/12 + i) = 18
Subtract -47/12 + i from both sides:
Answer:  f = 263/12 - i
7 0
3 years ago
a triangular prism has a base with a length of 6 in and a height of 8 cm. the height of the whole prism is 12 cm. What is the vo
777dan777 [17]
The volume of a prism of this type is 

v= (1/2) x B x h x H 

(1/2) x 15.24 x 8 x 12

= 732
6 0
3 years ago
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The ratio of the volume of soda in glass A to the volume of glass B is 8/3 to 7/2
MrRa [10]

Answer:

Total volume in the two glasses is 740 mL.

Step-by-step explanation:

Given:

Ratio of the volume of soda in glass A to the volume of glass B  =   8/3 : 7/2

Volume of soda in glass A = 320mL

To Find :

The total volume in the two glasses = ?

Solution:

Let the volume of soda in  glass B  be x

then

\text{ratio of soda in glass A} \times \text{ the volume of soda in glass B} = \text{ratio of soda in glass B} \times \text{ the volume of soda in glass A}

Substituting the values ,

\frac{8}{3} \times x  = \frac{7}{2} \times 320

\frac{8}{3} \times x  = \frac{2240}{2}

\frac{8}{3} \times x  = 1120

x  = 1120 \times \frac{3}{8}

x  = \frac{3360}{8}

x = 420

Now  total volume of soda in the two glasses

=> volume of soda in glass A + volume of soda in glass B

=> 320 + 420

=>740mL

5 0
3 years ago
NO LINKS!!<br><br>Solve each equation. Show all work.<br><br>(x - 2)^2 - 64 = 0​
klasskru [66]

(x-2)^2-64=0\\(x-2)^2=64\\x-2=8 \vee x-2=-8\\x=10 \vee x=-6

4 0
2 years ago
Read 2 more answers
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