Y = x² - 5x + 2
y = -6x + 4
-6x + 4 = x² - 5x + 2
0 = x² - 5x + 2 + 6x - 4
0 = x² + x - 2
(x + 2)(x - 1)
x = -2 ; x = 1
y = x² - 5x + 2 ; x = -2 y = x² - 5x + 2 ; x = 1
y = (-2)² - 5(-2) + 2 y = 1² - 5(1) + 2
y = 4 + 10 + 2 y = 1 - 5 + 2
y = 16 y = -2
y = -6x + 4 ; x = -2 y = -6x + 4 ; x = 1
y = -6(-2) + 4 y = -6(1) + 4
y = 12 + 4 y = -6 + 4
y = 16 y = -2
Choice C. <span>(-2, 16) and (1, -2) is the answer.</span>
Answer:
Cube root of 27 in radical form: ∛27???
Step-by-step explanation:
hope this helps
Answer:
Step-by-step explanation:
llllllllllllllllllllllllllllllllllllll
<em>l-37l=37 is the correct answer.</em>
