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mihalych1998 [28]
3 years ago
10

What is the cubed root of 27?​

Mathematics
2 answers:
marshall27 [118]3 years ago
8 0

Answer: As the cube root of 27 is a whole number, 27 is a perfect cube.

Cube root of 27 in radical form: ∛27.

I hope this answers you question.

Gnom [1K]3 years ago
5 0

Answer:

Cube root of 27 in radical form: ∛27???

Step-by-step explanation:

hope this helps

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What is f (x) = 4x + 1; {–4, –2, 0, 2, 4}
Reika [66]

Answer

4x+1

−4,−2,0,2,4

​

Step-by-step explanation:

5 0
3 years ago
3. A 5 ft tall person casts an 8 ft shadow, and stands next to a tree that casts a 65
NARA [144]

Answer:

104 ft

Step-by-step explanation:

The ratio of object to shadow is 5:8 and the tree is 65 so 65/5 is 13 and 13*8=104 so that's your answer! Sorry if it doesn't make to much sense.

6 0
2 years ago
Help please!<br>figure out the "inflection point" of the following function<br>f(x)=5x³ + 2x² − 3x​
Artyom0805 [142]

Answer:

x = -2/15.

Step-by-step explanation:

Finding the second derivative:

f'(x) = 15x^2 +4x - 3

f"(x) = 30x + 4

30x + 4 = 0   for a point of inflection

x = -4/30 =  -2/15

So 30x + 4 is negative up to x =  -2/15 and positive thereafter.

So the curve passes from concave downward to concave upward at x = -2/15.

3 0
3 years ago
Read 2 more answers
How to slove step by step
wariber [46]
\frac{x+3}{12} = \frac{2}{7}

Multiply both sides by 12, so that we get rid of the fraction in x.

12 · (x+3)/12 = 2/7 · 12

Simplify.

x + 3 = 24/7

Then, subtract 3 from both sides, so that "x" gets isolated.

x = 24/7 - 3

Turn "3" into an improper fraction so that we could find the value of x easier.

3 = 21/3

So :

x = 24/7 - 21/7

Simplify.

x = 3/7

~Hope this helps!~


7 0
3 years ago
Help!! Answer !!! about to run out of time in test!!
Gemiola [76]

\qquad \qquad\huge \underline{\boxed{\sf Answer}}

Here's the solution ~

Let's find the measure of hypotenuse first, by using Pythagoras theorem ;

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {8}^{2}  +  {6}^{2}

\qquad \sf  \dashrightarrow \: h {}^{2}  =  {36}^{}  +  {64}^{}

\qquad \sf  \dashrightarrow \: h {}^{2}  = 100

\qquad \sf  \dashrightarrow \: h {}^{}  =  \sqrt{100}

\qquad \sf  \dashrightarrow \: h {}^{}  =  {10}

Now, let's find the asked values ~

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{opposite \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \sin(x) =  \dfrac{3}{5}   \: or \: 0.6 \: units

For Cos y :

\qquad \sf  \dashrightarrow \:  \cos(y) =  \dfrac{adjcant \: side}{hypotenuse}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{6}{10}

\qquad \sf  \dashrightarrow \:  \cos(y)   = \dfrac{3}{5}  \: or \: 0.6 \: units

As we can see that both sin x and Cos y have equal values, therefore The required relationships is equality.

I.e Sin x = Cos y

Hope it helps ~

3 0
3 years ago
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