yeah. I can't see none of you work so help ME please.
< 1 and < 2 are vertical angles...because they are opposite angles made by two intersecting lines
< 3 and < 4 are adjacent....because they have a common side and a common vertex
The first one is 2x^2+2x-2
the second one is 2x^2-2x-2
the third one is 6h+6k
In the parallelogram ABCD, join BD.
Consider the triangle Δ ABD.
It is given that AB > AD.
Since, in a triangle, angle opposite to longer side is larger, we have,
∠ ADB > ∠ ABD. --- (1)
Also, AB || DC and BD is a transversal.
Therefore,
∠ ABD = ∠ BDC
Substitute in (1), we get,
∠ ADB > ∠ BDC.