1. Moles Fe = 209.7 g/ 55.847 g/mol= 3.75
The ratio between Fe and CO is 2 : 3
Moles CO = 3.75 x 3 /2 = 5.63
<span>Mass CO = 5.63 mol x 28.01 g/mol= 157.7 g
2. </span><span />2Na + 2H2O --> 2NaOH + H2<span>atomic weight of sodium is 23 48.7/23 = 2.12 moles of sodium
2.12/2 x 24 = 25.44dm^3 hydrogen = 1.06 moles
so multiply it by Avogadro's number1.06 X 6.02x10^23 = 1.204x10^24 molecules of hydrogen
</span>
Solidified, solidifying. 1. to make solid; make into a hard or compact mass; change from a liquid or gaseous to a solid form. 2. to unite firmly or consolidate.
Answer:
All their descendants will be heterozygous for the skin color, Bb, expressing blue skin.
Explanation:
<u>Available data</u>:
- Smurfette has light blue skin
- Her family is a "true bred" or "purebred" line.
- She married a boy who has light yellow skin
- blue skin is the dominant trait expressed by the B allele
- yellow skin is a recessive trait, expressed by the b allele
Cross: Smurfette x Husband
Parentals) BB x bb
Gametes) B B b b
Phenotypes) blue skin yellow skin
Punnett square)
B B
b Bb Bb
b Bb Bb
F1) 100% of the progeny will be heterozygous for the skin color, Bb
100% of the progeny will be blue-skinned.
Note: Although the progeny is blue-skinned, they are not true-bred anymore.
If two Bb guinea pigs cross, there are four possible outcomes:
- both pass the B: the son is BB
- one of the pass the B and the other pass the b: the son is Bb
- both pass the b: the son is bb
Since B (being black) is dominant, the son will be black in both BB and Bb cases. In order for a son to be brown, he must be a pure bb specimen.
So, if all of the offspring are black, it means that all four guinea pigs are either BB or Bb, which in turn means that at least one of the parents passed the B gene.
Relative date , which fossils in layers of rocks are placed in order from older to younger.
radiometric dating ,allows actual ages of actual rocks to be determined
