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Flura [38]
3 years ago
8

The following graph shows the time required to install fencing of different lengths.

Mathematics
2 answers:
Liono4ka [1.6K]3 years ago
6 0
The answer is letter A for your question
oksian1 [2.3K]3 years ago
3 0

Answer:A

Step-by-step explanation:

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A bookstore decides to divide its space into three sections: nonfiction books, novels, and stationery. The bookstore wants to de
Colt1911 [192]

Answer:

Stationery section will be 4 feet wide.

Step-by-step explanation:

Total area of bookstore = 288 sq ft

Area to be devoted to stationery = \frac{1}6 of total area = \frac{1}{6} \times 288 = 48\ sq\ ft

Length of stationery section = 12 ft

To find:

Width of stationery section = ?

Solution:

First of all, let us have a look at the area of rectangle:

A = Length \times Width

Here, we are given the length for stationery section and area of stationery section has been calculated above.

And we have to find the Width of stationery section.

So, let us put the two values to find the third value.

\Rightarrow 48 = 12 \times Width\\\Rightarrow Width = \dfrac{48}{12}\\\Rightarrow \bold{Width = 4\ ft}

So, the answer is:

Stationery section will be 4 feet wide.

3 0
3 years ago
Walter slater sells appliances and earns 2.5 percent commission in addition to his salary. last month he sold $63,000 in applian
Sveta_85 [38]

63,000 ÷ 100 = 630

630 x 2.5 = 1,575.00

4 0
3 years ago
Read 2 more answers
A 4 digit number that is divisible by 6 and 10
aliya0001 [1]

An example?

3600.

Hope this helps.

5 0
3 years ago
Read 2 more answers
I need help with these two questions please:) I need the answers fast ! Please and Thank You
Valentin [98]

Answer:

#1 is 9 times 10^15

#2 is 3 times 10^8

Step-by-step explanation:

4 0
3 years ago
4/5 divided by 1/3 plus 1/5 minus 3/5
r-ruslan [8.4K]

Answer:

  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

Step-by-step explanation:

Considering the expression

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

Solution Steps:

\frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}

as

\mathrm{Combine\:the\:fractions\:}\frac{1}{5}-\frac{3}{5}:\quad -\frac{2}{5}

so

=\frac{\frac{4}{5}}{\frac{1}{3}-\frac{2}{5}}    

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{\frac{b}{c}}{a}=\frac{b}{c\:\cdot \:a}

=\frac{4}{5\left(\frac{1}{3}-\frac{2}{5}\right)}

join  \frac{1}{3}-\frac{2}{5}:\quad -\frac{1}{15}

so

=\frac{4}{5\left(-\frac{1}{15}\right)}

\mathrm{Remove\:parentheses}:\quad \left(-a\right)=-a

=\frac{4}{-5\cdot \frac{1}{15}}

\mathrm{Apply\:the\:fraction\:rule}:\quad \frac{a}{-b}=-\frac{a}{b}

=-\frac{4}{5\cdot \frac{1}{15}}

\mathrm{Multiply\:}5\cdot \frac{1}{15}\::\quad \frac{1}{3}

so

=-\frac{4}{\frac{1}{3}}

\mathrm{Simplify}\:\frac{4}{\frac{1}{3}}:\quad \frac{12}{1}

so

=-\frac{12}{1}

\mathrm{Apply\:rule}\:\frac{a}{1}=a

=-12

Therefore

                  \frac{\frac{4}{5}}{\frac{1}{3}+\frac{1}{5}-\frac{3}{5}}=-12

4 0
3 years ago
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