The quadratic equation has two solutions if b^2 - 4ac > 0
Given the equation ax^4 + bx^2 + c=0
Substitute into the formula to have:
The equation becomes aP^2 + bP + c = 0
For us to have a unique solution, the discriminant b^2 - 4ac must be greater than zero. Hence the quadratic equation has two solutions if b^2 - 4ac > 0
learn more on discriminant here; brainly.com/question/1537997
Answer:
25 dollars times 0.20
Step-by-step explanation:
Here is your answer
A. (4,-7)
REASON:
In quadrant IV abscissa is +ve and ordinate is -ve. Since absolute value is 11
Here |4|+|-7|= 4+7= 11
HOPE IT IS USEFUL
