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Ronch [10]
4 years ago
15

Rationalise the denominator.

Mathematics
1 answer:
grin007 [14]4 years ago
7 0

Let's see what to do buddy...

_________________________________

To do this, we have to multiply the face and denominator of the fraction by the denominator conjunction, which is :

(5 -\sqrt{2})

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

Reminder :

(a + b)(a - b) =  {a}^{2} -  {b}^{2}  \\

°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°°

So we have :

\frac{1}{ 5-\sqrt{2} } \times  \frac{ 5+\sqrt{2}  }{ 5 +\sqrt{2}  } =  \frac{1 \times ( 5 +\sqrt{2}) }{(5- \sqrt{2} )( 5 +\sqrt{2})  } =  \\

The other is in the photo.

_________________________________

And we're done.

Thanks for watching buddy good luck.

♥️♥️♥️♥️♥️

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What are the coordinates of the point on the directed line segment from (-9, -1)(−9,−1) to (-9, -10)(−9,−10) that partitions the
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Answer:

Therefore the co-ordinate of the point on the line segment from (-9,-1) to(-9,-10) into a ratio internally is (-9,-7).

Therefore the co-ordinate of the point on the line segment from (-9,-1) to(-9,-10) into a ratio internally is (-9,-19).

Step-by-step explanation:

Given points are (-9,-1) and (-9,-10)

If a point divides the line segment by joining two points (x₁,y₁) and (x₂,y₂)  into a ratio m:n internally.

Then the point of the coordinate is (\frac{m.x_2+nx_1}{m+n},\frac{my_2+ny_1}{m+n}).

If a line segment is externally divided into a point by joining two points (x₁,y₁) and (x₂,y₂) with m: n ratio.

Then the point of the coordinate is (\frac{m.x_2-nx_1}{m-n},\frac{my_2-ny_1}{m-n}).

Internally

The co-ordinate of the point is (\frac{(-9)\times2+(-9)\times 1}{2+1},\frac{(-10)\times 2+(-1)\times 1}{2+1})

                                                 =(-9,-7)

Externally

The co-ordinate of the point is (\frac{(-9)\times2-(-9)\times 1}{2-1},\frac{(-10)\times 2-(-1)\times 1}{2-1})

                                                   =  (-9,-19)

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