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WITCHER [35]
2 years ago
8

Can you please help me I give you extra points ?

Mathematics
2 answers:
brilliants [131]2 years ago
7 0

Answer:

( -1 , -3 ) , ( 4 , -3 ) , (4 , -1 )

kkurt [141]2 years ago
6 0
Answer: 16 centimeters------nice computer by the way

Step-by-step explanation: addition

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Instructions: Find the common difference of the arithmetic sequence.<br> 7.05, 7.15, 7.25,7.35, 7.45
zzz [600]
I believe that the common difference would be.10
7 0
3 years ago
Read 2 more answers
Which number completes this number sentence? [ ? ] &gt; -6<br> A.-8<br> B.-7<br> C.-6<br> D.0
Xelga [282]

Answer:

It is 0

Step-by-step explanation:

Unlike the positive side of the number line which increases its value as it goes up in numbers, the negative side of a number line increases its value as it goes goes down in numbers as the more closer a negative number is to the positive side of infinity, the greater value it has. In this instance, zero is the greater number than -6 and all other negative numbers.

8 0
3 years ago
Solve the equation. Check your solution.
VladimirAG [237]
-5x/6  + 1=7/18
lowest common multiple=18
-15x+18=7
-15x=7-18
-15x=-11
x=-11/-15=11/15

The solution set is [11/15]

we check it out.
-5(11/15) /6    +  1 =7/18
(-55/15) / 6 +1=7/18
-55/90  +  1=7/18
(-55+90) /90=7/18
35/90=7/18
7/18=7/18
5 0
3 years ago
8(8-6v) is equaled to
horsena [70]

8(8-6v)=    using the distributive property

8*8 = 64

8*6v = 48v

8(8-6v) = 64-48v

6 0
3 years ago
The force of the wind blowing on a vertical surface varies jointly as the area of the surface and the square of the velocity. If
Ierofanga [76]

Answer:

a force of 1250lb is exerted

Step-by-step explanation:

since the force of the wind varies jointly as the area of the surface and the square of the velocity,

let f = force

a = area

velocity =v

from the above statement, we find out that

f \alpha a*v^2----1

that is f= k* a* v^2     -----2

where k is a coefficent of proportionality

since velocity of wind in mph,v =50

and force in lb = 20

and surface area =1/5 th ft^2

from eqn 2

we have that

20 =k*\frac{1}{5}* 50^2

making k subject of the formula

we have that

k =\frac{20}{\frac{1}{5} *50^2 } =\frac{1}{25} (lb.mph^-1.ft^-2)

that means that f =\frac{1}{25} *a *v^2  ---3

however, when velocity = 125mph

surface area =2ft^2

putting values in eqn 3 we have

f= \frac{1}{25}*2*125^2 = 1250 lb

hence a force of 1250lb is exerted

7 0
3 years ago
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