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3 years ago

Which is the hypothesis of this statement?

1 answer:

3 0

I agree with you.
The hypothesis is the part where the word <em>if </em>can be found. So, the hypothesis here has to be C. a and b are negative.

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figure a is a scale image of figure b the scale image that maps figure a onto figure b is 1:7 1/4 enter the value of x

skad [1K]

Answer: $x=21.75$

Step-by-step explanation:

You need to convert from mixed number to decimal number.

In order to do this, you can follow the steps shown below:

1. You must divide the numerator of the fraction by the denominator of the fraction.

2. Now you must add the quotient obtained to the Whole number part.

Then, you get:

$7\frac{1}{4}=7+0.25=7.25$

Then, the scale image that maps "Figure A" onto "Figure B" is:

$1:7.25$

Finally, in order to find the value of "x", you need to multiply the given length of the corresponding side of "Figure A" by $7.25$ .

Therefore, the result is:

$x=(3)(7.25)\\\\x=21.75$

3 0

3 years ago

A 6m ladder leans against a wall. The bottom of the ladder is 1.3m from the wall at time =0sec and slides away from the wall at

icang [17]

Answer:

- 0.100

Step-by-step explanation:

Length of the ladder, H = 6 m

Distance at the bottom from the wall, B = 1.3 m

Let the distance of top of the ladder from the bottom at the wall is P

Thus,

from Pythagoras theorem,

B² + P² = H² .

B² + P² = 6² ..............(1) [Since length of the ladder remains constant]

at B = 1.3 m

1.3² + P² = 6²

P² = 36 - 1.69

P² = 34.31

P = 5.857

Now,

differentiating (1)

$2B(\frac{dB}{dt})+2P(\frac{dP}{dt})=0$

at t = 2 seconds

change in B = 0.3 × 2= 0.6 ft

Thus,

at 2 seconds

B = 1.3 + 0.6 = 1.9 m

therefore,

1.9² + P² = 6²

P = 5.69 m

on substituting the given values,

2(1.9)(0.3) + 2(5.69) × $(\frac{dP}{dt})$ = 0

1.14 + 11.38 × $(\frac{dP}{dt})$ = 0

11.38 × $(\frac{dP}{dt})$ = - 1.14

$(\frac{dP}{dt})$ = - 0.100

here, negative sign means that the velocity is in downward direction as upward is positive

5 0

4 years ago

Which of the following statements is needed in order to prove these triangles are congruent by AAS?

creativ13 [48]

Answer:

$RQ\cong UT$

Step-by-step explanation:

Two triangles are congruent by AAS postulate if two adjacent corresponding angles are congruent and the next adjacent sides to any of the angles is are also congruent. The adjacent sides should not be in between the two congruent angles.

From the triangles RQS and UTV

$\angle R\cong \angle U\\\angle S\cong \angle V$

The adjacent side to $\angle R$ is RQ and for $\angle U$ is UT.

Similarly, the adjacent side to $\angle S$ is QS and for $\angle V$ is TV.

So, the possible sides that could be congruent by AAS postulate are:

$RQ\cong UT$ or $QS\cong TV$

So, the correct option is $RQ\cong UT$

5 0

3 years ago

What is 0.37 divided to5.18

erik [133]

.37 divided to 5.18 = 14

First you move the decimals of .37 to the right and add two zeros since u moved to places to the right. Then 37 can go into 51800 14 times

3 0

3 years ago

If you bought a stock last year for a price of $126, and it has gone down 13% since then, how much is the stock worth now, to th

Klio2033 [76]

It is now $109.62. You would multiply .13 (13%) by 126 which would give you 16.38. You would then subtract 126-16.38 to get 109.62.

4 0

3 years ago

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