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Luden [163]
2 years ago
14

PLEASE HELP ME WITH THIS PROBLEM

Mathematics
1 answer:
irina [24]2 years ago
4 0

Answer:

In astronomy, geography, and related sciences and contexts, a direction or plane passing by a given point is said to be vertical if it contains the local gravity direction at that point. Conversely, a direction or plane is said to be horizontal if it is perpendicular to the vertical direction

Step-by-step explanation:

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P=1/4q+8 make q the subject​
Daniel [21]

Answer:

q = 4p - 32

Step-by-step explanation:

P = 1/4q + 8

Making q the subject

P - 8 = 1/4q

Divide both sides by 1/4

q = (p - 8) ÷ 1/4

= (P - 8) × 4/1

= 4p - 32

q = 4p - 32

6 0
3 years ago
PLEASE HELP ASAP PLEASE WILL GIVE BEST RATE AND BRAINLEST PLEASE​
natima [27]

Answer:

I think it's 145.225 sq in.

Step-by-step explanation:

2.5 x 2 x 3.14 = 15.7

15.7 x 9.25 = 145.225

8 0
3 years ago
Read 2 more answers
What is the simplified version of 3\sqrt{135}
Aleonysh [2.5K]

Answer:

The simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

Step-by-step explanation:

The given expression is

\sqrt[3]{135}

According to the property of radical expression.

\sqrt[n]{x}=(x)^{\frac{1}{n}}

Using this property we get

\sqrt[3]{135}=(135)^{\frac{1}{3}}

\sqrt[3]{135}=(27\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3\times 5)^{\frac{1}{3}}

\sqrt[3]{135}=(3^3)^{\frac{1}{3}}\times (5)^{\frac{1}{3}}      [\because (ab)^x=a^xb^x]

\sqrt[3]{135}=3\times \sqrt[3]{5}     [\because \sqrt[n]{x}=(x)^{\frac{1}{n}}]

\sqrt[3]{135}=3\sqrt[3]{5}

Therefore the simplified version of \sqrt[3]{135} is 3\sqrt[3]{5}.

7 0
3 years ago
Read 2 more answers
What do you notice about the angle measures?
Aleksandr-060686 [28]
1. Two angles are acute, while the other is square

2. They all add up to 180°
7 0
2 years ago
The fish population of Lake Collins is decreasing at a rate of 5% per year. In 2004 there were about 1,350 fish. Write an expone
ad-work [718]

Answer:

Part 1) The exponential function is equal to y=1,350(0.95)^{x}

Part 2) The population in 2010 was  992\ fish

Step-by-step explanation:

Part 1) Write an exponential decay function that models this situation

we know that

In this problem we have a exponential function of the form

y=a(b)^{x}

where

y ----> the fish population of Lake Collins since 2004

x ----> the time in years

a is the initial value

b is the base

we have

a=1,350\ fish

b=(100\%-5\%)=95\%=0.95

substitute

y=1,350(0.95)^{x} ----> exponential function that represent this scenario

Part 2) Find the population in 2010

we have

y=1,350(0.95)^{x}

so

For x=(2010-2004)=6\ years

substitute

y=1,350(0.95)^{6}=992\ fish

7 0
3 years ago
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