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4 years ago

7

The length of a rectangle is five times its width. if the perimeter of the rectangle is 96 yd , find its area.

1 answer:

elena-14-01-66 [18.8K]4 years ago

3 0

Rectangle has 4 sides dived 96 by 4 and then from there you have to make length be bigger than width

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Ksju [112]

Y=x^2-6x+14
=x^2-6x+9-9+14
x^2-3x-3x+9 +5
x(x-3)-3(x-3)+5
(x-3)^2+5
here h=3

minimum value would be 5

8 0

3 years ago

What is the value of x?

lbvjy [14]

The vaue of x is 23 cm

5 0

3 years ago

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The U.S. Flag has 50 white stars, 6 white stripes, and 7 red stripes. What is the relationship between stars and total stripes?

Svetradugi [14.3K]

Answer:

The relationship between stars and total stripes are 50 : 13.

Step-by-step explanation:

When you add all the stripes, it equals 13. There are 50 stars so this is the answer.

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3 years ago

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1. Fill in the blanks for the rules for working with exponents:

natima [27]

1.a)add
B) substract
C) multiply
D) one

2) 1002=1.002×10^3

3)2.8×10^-3 < 2.5×10^-2 < 1.2×103 <4×103

5 0

3 years ago

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The probability that a male will be colorblind is .042. Find the probabilities that in a group of 53 men, the following are true

Dvinal [7]

Answer:

See below for answers and explanations

Step-by-step explanation:

<u>Part A</u>

$\displaystyle P(X=x)=\binom{n}{x}p^xq^{n-x}\\\\P(X=5)=\binom{53}{5}(0.042)^5(1-0.042)^{53-5}\\\\P(X=5)=\frac{53!}{(53-5)!*5!}(0.042)^5(0.958)^{48}\\\\P(X=5)\approx0.0478$

<u>Part B</u>

$P(X\leq5)=P(X=1)+P(X=2)+P(X=3)+P(X=4)+P(X=5)\\\\P(X\leq5)=\binom{53}{1}(0.042)^1(1-0.042)^{53-1}+\binom{53}{2}(0.042)^2(1-0.042)^{53-2}+\binom{53}{3}(0.042)^3(1-0.042)^{53-3}+\binom{53}{4}(0.042)^4(1-0.042)^{53-4}+\binom{53}{1}(0.042)^5(1-0.042)^{53-5}\\\\P(X\leq5)\approx0.9767$

<u>Part C</u>

$\displaystyle P(X\geq 1)=1-P(X=0)\\\\P(X\geq1)=1-(1-0.042)^{53}\\\\P(X\geq1)\approx1-0.1029\\\\P(X\geq1)\approx0.8971$

6 0

2 years ago