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Licemer1 [7]
3 years ago
13

Please answer see the image below

Mathematics
2 answers:
Marianna [84]3 years ago
6 0

Answer:

<h2>37.7 </h2><h2 />

Step-by-step explanation:

perimeter of semicircle = 1/2 π d

                                       = 1/2 π (6)

                                       = 9.425 x 4 semicircles

                                       = 37.7

lutik1710 [3]3 years ago
3 0

Answer:

P=37,68

Step-by-step explanation:

Those are 4 semi-circles, so basically 2 circles

The diameter of the circles d=6

p =2 \times  d \times \pi

p = 2 \times 6 \times 3.14

P=37,68

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Michael bought six books that cost d dollars each.Write an equation that can be used to show the total cost (c)of the books?How
yulyashka [42]

Step-by-step explanation:

Equation is 6d (6 • d)

Actual Question:

c = 6d

Let d = 7.89

c= 6 (7.89)

c = 47.34

Michael would have spent a total of $47.34.

8 0
3 years ago
Read 2 more answers
25 pts, please help ASAP
andrew-mc [135]

Answer:

5t - 2t = 84 - 54

3t = 30

t = 30/3

t = 10.

3 0
3 years ago
Yo help me with number 6 pls thx and tell me how. I can't find the answer
dybincka [34]
First find the formula which is A(N)=A+(N-1)D then fill in what you know
N=term your looking for
A=first term
D= common diffrence

Once filled in you will get this 18(18)=18+(18-1)-6
then solve to get 324= -84

Your final answer is that the 18th term is -84

Hope I could help
6 0
3 years ago
A car is traveling at an average speed of 80km/h.What is it's speed in meters per second (m/s)​
jekas [21]

Answer:

22.21 m/s

Step-by-step explanation:

1 hour = 80km

1 minute = 80000 ÷ 60 = 1.333km

1 second = 1.333 ÷ 60 = 22.21

4 0
3 years ago
Can somone help me with number 23 and 24
tangare [24]

23.

store price = 14 + 0.5(14)

store price = 21

customer price = 21 + 0.08(21)

customer price = 21 + 1.68

customer price = $22.68

24.

formula: A = P(1 + rt)

A = 140(1 + (0.03)(2))

A = 140(1.06)

A = 148.40

interest = 148.40 = 140

interest = $8.40

Hope this helps!! :)

7 0
3 years ago
Read 2 more answers
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