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Licemer1 [7]
3 years ago
13

Please answer see the image below

Mathematics
2 answers:
Marianna [84]3 years ago
6 0

Answer:

<h2>37.7 </h2><h2 />

Step-by-step explanation:

perimeter of semicircle = 1/2 π d

                                       = 1/2 π (6)

                                       = 9.425 x 4 semicircles

                                       = 37.7

lutik1710 [3]3 years ago
3 0

Answer:

P=37,68

Step-by-step explanation:

Those are 4 semi-circles, so basically 2 circles

The diameter of the circles d=6

p =2 \times  d \times \pi

p = 2 \times 6 \times 3.14

P=37,68

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Find the volume of the triangular prism."<br> 14 ft<br> h=3A<br> 6 ft
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Step-by-step explanation:

volume =triangular area× length

=1/2×6×3×14

=126 ft³

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At the stadium, the Grandstands, Bleachers and Box Seats cost $6.75, $4.50 and $10.50, respectively. If you have $80, then how m
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4 years ago
Lowest common multiple of 6 , 7 and 8
Shalnov [3]

Answer:

The LCM is 168

Step-by-step explanation:

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Please help me. Explanation needed in algebraic form:
egoroff_w [7]

Answer:

the new frame is bigger than the original frame by 10%

Step-by-step explanation:

Let the length of the original frame be l,

then it's width is (10% of l)=\frac{10}{100}×l

                                           =\frac{l}{10}

hence area of original frame=A=length×width

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now the length of frame is enlarged by 10%

new lenght of frame=l+10%×l

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                                  =\frac{11}{10}×l

width of new frame==\frac{l}{10}

area of new frame=length×width

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4 0
3 years ago
he time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the a
Eva8 [605]

Answer:

The answer is below

Step-by-step explanation:

The time between arrivals of small aircraft at a county airport is exponentially distributed with a mean of one hour. Round the answers to 3 decimal places.

(a) What is the probability that more than three aircraft arrive within an hour?

(b) If 30 separate one-hour intervals are chosen, what Is the probability that no interval contains more than three arrivals?

(c) Determine the length of an interval of time (in hours) such that the probability that no arrivals occur during the interval is 0.1.

Solution:

a) A poisson distribution is given by the formula:

P(X=x)=\frac{e^{-\lambda }\lambda^x}{x!}

λ = 1 hour

Therefore:

P(X > 3) = 1 - P(X < 3) = 1 - [P(X = 0) + P(X = 1) + P(X = 2) + P(x = 3)]

P(X=0)=\frac{e^{-1}*1^0}{0!}=0.3679

P(X=1)=\frac{e^{-1}*1^1}{1!}=0.3679

P(X=2)=\frac{e^{-1}*1^2}{2!}=0.1839

P(X=3)=\frac{e^{-1}*1^3}{3!}=0.0613

P(X > 3) = 1 - [0.3679+0.3679 + 0.1839 + 0.0613] = 0.019

b) Assuming 30 1 hour intervals, hence:

P(X \leq 3)^{30}=[1-P(X\geq 30)]^{30}=(1-0.019)^{30}=0.5624

c) mean = 1 hour

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1 = 1 / λ

λ = 1

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F(x)=1-e^{-\lambda x}

0.1=1-F(x)\\\\0.1=1-(1-e^{- x})\\\\0.1=e^{- x}\\\\-x=ln(0.1)\\\\-x = -2.3\\\\x=2.3\ hours

4 0
3 years ago
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