4, 7 and 9 are mutually coprime, so you can use the Chinese remainder theorem.
Start with
Taken mod 4, the last two terms vanish and we're left with
We have 
, so we can multiply the first term by 3 to guarantee that we end up with 1 mod 4.
Taken mod 7, the first and last terms vanish and we're left with
which is what we want, so no adjustments needed here.
Taken mod 9, the first two terms vanish and we're left with
so we don't need to make any adjustments here, and we end up with 
.
By the Chinese remainder theorem, we find that any 
such that
is a solution to this system, i.e. 
for any integer 
, the smallest and positive of which is 149.
For this question I would put the problem into slope-intercept form or y=mx+b. So add 3x to both sides so that the equation becomes y=3x+3 Then this equation is easier to graph. the y-intercept is 3 so there is a point at (0,3). and the slope is 3 so you would go over 1 up 3. Then connect those points and you have finished the graph. Hope this helps.
The true statement about the circle with center P is that triangles QRP and STP are congruent, and the length of the minor arc is 11/20π
<h3>The circle with center P</h3>
Given that the circle has a center P
It means that lengths PQ, PR, PS and PT
From the question, we understand that QR = ST.
This implies that triangles QRP and STP are congruent.
i.e. △QRP ≅ △STP is true
<h3>The length of the minor arc</h3>
The given parameters are:
Angle, Ф = 99
Radius, r = 1
The length of the arc is:
L = Ф/360 * 2πr
So, we have:
L = 99/360 * 2π * 1
Evaluate
L = 198/360π
Divide
L = 11/20π
Hence, the length of the minor arc is 11/20π
Read more about circle and arcs at:
brainly.com/question/3652658
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