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denis-greek [22]
3 years ago
5

What integer values satisfy both inequalities? -1≤x<3 x<2

Mathematics
1 answer:
Margaret [11]3 years ago
5 0

Answer:

okokokokkokkolkkokkk

You might be interested in
PLEASE HELP ITS DUE TODAY!!
Cerrena [4.2K]
If you divide 9 by 25 it equals .36
if you divide 18 by 50 it equals .36
if you divide 36 by 100 it equals .36
and if you divide 9 by 25 it equals .36
therefor it’s all equivalent. 18 divided by 50 is also .36

3 0
3 years ago
What value of x makes the equation true?<br> 1-3x = 1 - x
Natasha_Volkova [10]

Answer:

\boxed{ \bold{ \huge{ \boxed{ \sf{0}}}}}

Step-by-step explanation:

\sf{1 - 3x = 1 - x}

Move x to left hand side and change it's sign

Similarly, move 1 to right hand side and change it's sign

\dashrightarrow{ \sf{ - 3x + x = 1 - 1}}

Collect like terms

\dashrightarrow{ \sf{ - 2x = 0}}

Divide both sides by -2

\dashrightarrow{ \sf{ \frac{ - 2x}{ - 2}  =  \frac{ 0}{ - 2}}}

Calculate

\dashrightarrow{ \sf{ x = 0}}

Hope I helped!

Best regards! :D

5 0
3 years ago
If using the method of completing the square to solve the quadratic equation x2 −4x+13=0, which number would have to be added to
stiv31 [10]
X²-4x+(4/2)²-(4/2)²+13=0
x²-4x+4-4+13=0


-4 should be added



Mark brainliest please
7 0
3 years ago
What is the image point of (8, -9) after the transformation R90° 0 T5,-2?
krok68 [10]

Given:

The point is (8,-9).

Rule of transformation R(90^\circ,0)\circ T.

To find:

The image of given point after transformation.

Solution:

Consider the give point is P(8,-9).

Rule of transformation R(90^\circ,0)\circ T represents translation T<5,-2> after that rotation 90 degrees counter clockwise.

If a figure translated by T<5,-2>, then

(x,y)\to (x+5,y-2)

P(8,-9)\to P'(8+5,-9-2)

P(8,-9)\to P'(13,-11)

If a figure rotated 90 degrees counter clockwise, then

(x,y)\to (-y,x)

P'(13,-11)\to P''(-(-11),13)

P'(13,-11)\to P''(11,13)

Therefore, the image of point (8,-9) after transformation is (11,13).

6 0
3 years ago
the ramirez family comes home from vacation to find their mailbox overflowing with mail. there are 6 more magazines than there a
nirvana33 [79]

Answer:

9 magazines

Step-by-step explanation:

To solve this problem you will want to work backwards. Start with the junk mail. There is 18 junk mail and if there are 1/3 as many bills as junk mail then you will need to multiply 18 * 1/3. This equals 6 bills. If there is twice as many bills as letters then you will need to divide bills(6) by 2 which equals 3. If there are 6 more magazines than letters then you need to add 6 to the letters (3). 3 + 6 = 9

4 0
3 years ago
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