Option a is correct. The calculated answer is 0.150
<h3>How to get the value using the cdf</h3>In order to get P(0.5 ≤ X ≤ 1.5).
This can be rewritten as
p = 0.5
and P = 1.5
We have the equation as
This would be written as
1.5²/16 - 0.5²/16
= 0.1406 - 0.015625
= 0.124975
This is approximately 0.1250
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<h3>complete question</h3>Use the cdf to determine P(0.5 ≤ X ≤ 1.5).
a) 0.1250
b) 0.0339
c) 0.1406
d) 0.0677
e) 0.8750
f) None of the above
Answer:
0.6210
Step-by-step explanation:
Given that a Food Marketing Institute found that 39% of households spend more than $125 a week on groceries
Sample size n =87
Sample proportion will follow a normal distribution with p =0.39
and standard error =
the probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41
=
There is 0.6210 probability that the sample proportion of households spending more than $125 a week is between 0.29 and 0.41