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densk [106]
3 years ago
14

What is the value of x in this figure? 282√ 28 143√ 283√ A right triangle with one of the acute angles labeled 30 degrees. The h

ypotenuse is labeled x. The leg across from 30 degree angle is labeled 14.
Mathematics
1 answer:
amid [387]3 years ago
6 0

Using the law of sines:

Sin (angle) = opposite leg / hypotenuse

Sin(30) = 14 /x

x = 14 * sin(30)

x = 28

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Answer:

3-4 no 4-3=1

Step-by-step explanation:

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2 years ago
Layla lives in Colorado and works as a teacher earning $55,000 a year. Her brother A.J. lives in Nevada and works as a teacher,
likoan [24]

Answer:

<u>Because Nevada is one of the seven states where residents no pay income tax, no matter how much you make. This decision is compensated with a higher-than-average sales tax.</u>

Step-by-step explanation:

1. Let's check the information provided to us to answer the question correctly:

Layla annual earnings = US$ 55,000

A.J. annual earnings = US$ 55,000

Income tax rate paid by Layla = 4.63%

Income tax rate paid by A.J. = 0%

2. Colorado uses these taxes to pay for public services such as school, police, and sanitation. A.J. pays 0 percent of his yearly income to the state of Nevada in income taxes. Yet his town has schools, police, and sanitation services. Why does this happen?

Because Nevada is one of the seven states where residents no pay income tax, no matter how much you make. This decision is compensated with a higher-than-average sales tax.

7 0
3 years ago
Solve the inequality for x.<br> 7 &gt; 2x+9
Advocard [28]

Answer:

<h2>x<-1</h2>

Step-by-step explanation:

7 > 2x+9\\\\\mathrm{Switch\:sides}\\\\\mathrm{Subtract\:}9\mathrm{\:from\:both\:sides}\\\\2x+9-9

5 0
2 years ago
Millie works 8 hours on Saturday and earns £6.50 an hour. Her bus fare to work costs £2.75 and she also spends £4.25 on her lunc
hram777 [196]
The answer is 14% or 0.14
3 0
3 years ago
Start with the geometric power series LaTeX: 1+x+x^2+x^3+x^4+\cdots Substitute LaTeX: -x^3in place of LaTeX: x, and then take a
valina [46]

Answer:

-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}

Step-by-step explanation:

Given : 1+x+x^2+x^3+x^4+\cdots

On putting -x^3 in place of x , we get 1+\left ( -x^3 \right )+\left ( -x^3 \right )^2+\left ( -x^3 \right )^3+\left ( -x^3 \right )^4+...

On simplifying , we get 1-x^3+x^6-x^9+x^{12}+...

On differentiating , we get \left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...

Here ,

-3x^2=\left ( -1 \right )^1\,3(1)x^{3(1)-1}\\6x^5=\left ( -1 \right )^2\,\,3(2)\,\,x^{3(2)-1}\\-9x^8=\left ( -1 \right )^3\,\,3(3)\,\,x^{3(3)-1}\\12x^{11}=\left ( -1 \right )^4\,\,3(4)\,\,x^{3(4)-1}

Now , we need to express it using summation notation.

\left ( 1-x^3+x^6-x^9+x^{12}+... \right )'=-3x^2+6x^5-9x^8+12x^{11}+...=\sum_{n=1}^{\infty }\left ( -1 \right )^n\,\,3n\,\,x^{3n-1}

4 0
3 years ago
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