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3 years ago

Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.

Mathematics

1 answer:

ki77a [65]3 years ago

6 0

The question is not well presented and the question also requires an attachment which is missing. See complete question below

Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.

a. 12/24 = 18/16 = ½

b. 12/18 = 16/24 = ⅔

c. 12/16 = 18/24 = ¾

d. 18/12 = 24/16 = 3/2

Answer:

c. 12/16 = 18/24 = ¾

Step-by-step explanation:

Given

Two similar triangles

Required

Ratio of corresponding sides

To solve questions like this, you have to make comparisons between the similar sides of the triangle.

From the attached file,

Side PQ is similar to Side AB

And

Side QR is similar to Side BC

Also from the attached file

PQ = 12 and QR = 18

AB = 16 and BC = 24

Now, the ratio can be calculated.

Ratio = PQ/AB or QR/BC

Ratio = PQ/AB

Ratio = 12/16

Divide numerator and denominator by 4

Ratio = ¾

Ratio = QR/BC

Ratio = 18/24

Divide numerator and denominator by 6

Ratio = ¾.

Combining these results

Ratio = 12/16 = 18/24 = ¾

Hence, option C is correct

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3 years ago

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HELP i know this is simple but i cant seem to find the correct equation

valentinak56 [21]

<h3>Answer: g(x) = (-2/3)*x^2</h3>

============================================

Work Shown:

f(x) = x^2

g(x) = a*f(x) for some constant 'a' since g(x) is a scaled version of f(x).

The value of 'a' vertically stretches f(x) upward if a > 0

If 'a' is negative, then we have a reflection going on as shown in the diagram.

We want (x,y) = (3,-6) to be on the graph of g(x). This means g(3) = -6

If we plugged x = 3 into f(x), we get

f(x) = x^2

f(3) = 3^2

f(3) = 9

So,

g(x) = a*f(x)

g(3) = a*f(3) ... replace x with 3

g(3) = a*9 ... replace f(3) with 9 since f(3) = 9

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3 years ago

A handbag contains five coins, four keys,

Dmitry [639]

The expected number of mints taken out of the handbag = 0.94

For given question,

We have been given that a handbag contains five coins, four keys,

and eight mints.

Total number of items in the handbag would be,

= 5 coins + 4 keys + 8 mints

= 17 items

So, the total number of items in a handbag = 17

Here, two items are taken out of the handbag one after the other and not replaced.

We need to find the expected number of mints taken out of the handbag.

Number of items taken out = 2

Let x be the number of mints taken out of the handbag.

x can be 0, 1, or 2

For x = 0,

the two items taken out could be either coins or keys.

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So, the 1st pick = 9/17

and 2nd pick = 8/16

⇒ P(x = 0) = 9/17 × 8/16

⇒ P(x = 0) = 72/272

For x = 1,

Assume that in the 1st pick mint is taken out.

So, 1st pick = 8/17

For second pick, it can be either coin or key.

This means, there are two possibilities for the second pick.

so, 2nd pick = 2 × 9/16

⇒ P(x = 1) = 8/17 × 9/16 × 2

⇒ P(x = 1) = 144/272

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Learn more about the probability here:

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2 years ago

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