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pickupchik [31]
3 years ago
7

Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.

Mathematics
1 answer:
ki77a [65]3 years ago
6 0

The question is not well presented and the question also requires an attachment which is missing. See complete question below

Write the ratio of corresponding sides for the similar triangles and reduce the ratio to lowest terms.

a. 12/24 = 18/16 = ½

b. 12/18 = 16/24 = ⅔

c. 12/16 = 18/24 = ¾

d. 18/12 = 24/16 = 3/2

Answer:

c. 12/16 = 18/24 = ¾

Step-by-step explanation:

Given

Two similar triangles

Required

Ratio of corresponding sides

To solve questions like this, you have to make comparisons between the similar sides of the triangle.

From the attached file,

Side PQ is similar to Side AB

And

Side QR is similar to Side BC

Also from the attached file

PQ = 12 and QR = 18

AB = 16 and BC = 24

Now, the ratio can be calculated.

Ratio = PQ/AB or QR/BC

Ratio = PQ/AB

Ratio = 12/16

Divide numerator and denominator by 4

Ratio = ¾

Or

Ratio = QR/BC

Ratio = 18/24

Divide numerator and denominator by 6

Ratio = ¾.

Combining these results

Ratio = 12/16 = 18/24 = ¾

Hence, option C is correct

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Z= (X1`-X2`)- (u1-u2)/\sqrt{ \frac{ s_1^2}{n_1^2} +\frac{ s_2^2}{n_2}   (here s1=σ1 and s2= σ2)

Step-by-step explanation:

Let  X1` be the mean of the first random sample of size n1 from a normal population with a mean u1 and known standard deviation σ1.Let  X2` be the mean of the second random sample of size n2 from another normal population with a mean u2 and known standard deviation σ2. Then the sampling distribution of the difference X1`-X2` is normally distributed with a mean of u1-u2 and a standard deviation of

\sqrt{ \frac{ s_1^2}{n_1^2} +\frac{ s_2^2}{n_2} .  (here s1=σ1 and s2= σ2)  In other words the variable

Z= (X1`-X2`)- (u1-u2)/\sqrt{ \frac{ s_1^2}{n_1^2} +\frac{ s_2^2}{n_2}   (here s1=σ1 and s2= σ2)

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4) Find the rejection region

5)Compute the value of Z from the sample data

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