Ask question

Ask question

All categories

Katyanochek1 [597]

3 years ago

5

jared charges 18 cents per square inch for his frames. how much will he charge for a frame that measures 16 inches on each side

and has a width of 2 inches

1 answer:

kogti [31]3 years ago

5 0

Find the area

the area=length times width=16 times 2=32 square inches
32 times amount charged per square inch=32 times 18=576 cents

costs $5.76

You might be interested in

Joe Bob wanted to find out how many hours of exercise the students at his school gets each week. He went to the school's gym and

gayaneshka [121]

Although I am unsure what this question has to do with Mathematics, Joe Bob could simply say "How often do you work out in a week?"

4 0

3 years ago

What reasoning and explanations can be used when solving radical equations and how do extraneous solutions arise from radical eq

Mkey [24]

Answer:

We know that, a 'radical equation' is an equation that contains radical expressions, which further are the expressions containing radicals ( square roots and other roots of numbers ).

In order to solve radical equations, we use the rules of exponents and basic algebraic properties.

The common reasoning to use while solving a radical equation is:

1. Isolate the radical expression.

2. Square both sides of the equation to remove radical.

3. After removing the radical, solve the equation to find the unkown variable

4. Check the answer for the errors occurred by removing the radicals.

For e.g. $\sqrt{x}-3=5$

i.e. $\sqrt{x}-3+3=5+3$ ( Adding 3 on both sides )

i.e. $\sqrt{x}=8$

i.e. $(\sqrt{x})^{2} =8^{2}$

i.e. $x=64$ .

So, the solution the the radical equation $\sqrt{x}-3=5$ is x = 64.

Further, we know that an 'extraneous solution' is that root of the radical equation which is not a root of the original equation and is excluded from the domain.

for e.g. Take $\sqrt{x+4} =x-2$

i.e. $(\sqrt{x+4})^{2} =(x-2)^2$

i.e. $x+4=x^2+4-4x$

i.e. $0=x^2-5x$

i.e. $0=x(x-5)$

i.e. x = 0 and x = 5.

Substituting x = 0 in $\sqrt{x+4} =x-2$ , gives $\sqrt{0+4} =0-2$ i.e. $\sqrt{4} =-2$ i.e. $2=-2$ , which is not possible.

So, x = 0 is a solution that does not satisfy the equation.

Hence, x = 0 is an extraneous solution.

7 0

3 years ago

Write 1 3/4 as a decimal number.

taurus [48]

Answer:

The answer is 1.705 in decimals

6 0

3 years ago

George's page contains twice as many type words as Bill's paid and Bill's page contains 50 fewer words and Charlie's page. If ea

defon

For this, we use simultaneous equations. Let George's page be g, Charlie's be c and Bill's page be b.

First, <span>George's page contains twice as many type words as Bill's.

Thus, g = 2b.

</span><span>Second, Bill's page contains 50 fewer words than Charlie's page.

Thus, b = c - 50.

</span>If each person can type 60 words per minute, after one minute (i.e. when 60 more words have been typed) <span>the difference between twice the number of words on bills page and the number of words on Charlie's page is 210.

We can express that as 2b - c = 210.

Now we need to find b, since it represents Bill's page.

We can substitute b for (c - 50) since b = c - 50, into the equation 2b - c = 210. This makes it 2(c - 50) - c = 210.

We can expand this to 2c - 100 - c = 210.

We can simplify this to c - 100 = 210.

Add 100 to both sides.

c - 100 + 100 = 210 + 100

Then simplify: c = 210 + 100 = 310.

Now that we know c, we can use the first equation to find b.

b = c - 50 = 310 - 50 = 260.

260 is your answer. I don't know where George comes into it. Maybe it's a red herring!</span>

8 0

3 years ago

Read 2 more answers

one bucket of gravel has a mass of 7.05 kilograms. what is the mass for 20 buckets of gravel in kilograms

Westkost [7]

Answer:

tell me if am wrong.

Step-by-step explanation:

1 bucket=7.05kg

20 bucket=20*7.05=141 kg

the mass of 20 bucket is 141 kilogram(kg)

5 0

3 years ago