Answer:
37 dimes and 10 nickels
Step-by-step explanation:
let d = # dimes
let n = # nickels
we can set up a system of equations:
n + d = 47
.05n + .10d = 4.2
if we solve the first equation for 'n' we get:
n = 47-d
now we can substitute this in for 'n' in the second equation:
.05(47-d) + .10d = 4.2
2.35 - .05d + .10d = 4.2
2.35 + .05d = 4.2
subtract 2.35 from each side to get:
.05d = 1.85
d = 1.85÷.05
d = 37
if d+n = 47 and d=37 then n = 10
Check:
.05(10) + .1(37) should equal 4.2
.50 + 3.7 = 4.2 [It Checks Out]
Answer:
19 seconds.
Step-by-step explanation:
Given that the clock was exactly on time at 7am, and at 1pm the clock was 228 seconds late, to determine, at that rate, how slow was the clock half an hour, the following calculation must be performed:
1 PM = 13:00
13 - 7 = 6
228/6 = 38
38/2 = 19
Thus, every half hour the clock is delayed 19 seconds.
Answer:
B. l = (S - πr^2) / πr
Step-by-step explanation:
S = πrl + πr^2 solve for l
πrl = S - πr^2
l = (S - πr^2) / πr
Answer is B. l = (S - πr^2) / πr
Step-by-step explanation:
-5 × -5 = 25
-6 + 5 = 1
-3 + 5 = -8
Answer: y=−2x+1
Step-by-step explanation:
