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Gemiola [76]
3 years ago
15

At the party, 6/16 of the guest were playing games and 3/8 of the guest were singing.Pat said that the number of guest were play

ing games as were singing .Is she right?Explain
Mathematics
2 answers:
ziro4ka [17]3 years ago
8 0
Yes.  6/16 simplifies to 3/8, which is the same amount of people singing.
IgorLugansk [536]3 years ago
5 0
Yes because half of 6/16 is 3/8
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A factory made 845 pairs of shoes in January. These shoes were sent to three shoe stores and one outlet mall. The number of pair
Semenov [28]
Answer=65 pairs of shoes

Given the data, the following equation can be made where x is equal to the number of shoes sent to the outlet mall.

845=4x+4x+4x+x
845=13x
divide both sides by 13
65=x

65 pairs of shoes were sent to the outlet mall
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3 years ago
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There is a closed carton of eggs in Mai's refrigerator. The carton contains e eggs and it can hold 12 eggs. What are some possib
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Answer:

1,2,3,4,5,6,7,8,9,10,11

Step-by-step explanation:

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A phycologist is interested in determining the proportion of algae samples from a local rivulet that belong to a particular phyl
LuckyWell [14K]

Answer:

A sample of 16577 is required.

Step-by-step explanation:

In a sample with a number n of people surveyed with a probability of a success of \pi, and a confidence level of 1-\alpha, we have the following confidence interval of proportions.

\pi \pm z\sqrt{\frac{\pi(1-\pi)}{n}}

In which

z is the z-score that has a p-value of 1 - \frac{\alpha}{2}.

The margin of error is of:

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

99% confidence level

So \alpha = 0.01, z is the value of Z that has a p-value of 1 - \frac{0.01}{2} = 0.995, so Z = 2.575.

She wants to estimate the proportion using a 99% confidence interval with a margin of error of at most 0.01. How large a sample size would be required?

We have no estimation for the proportion, and thus we use \pi = 0.5, which is when the largest sample size will be needed.

The sample size is n for which M = 0.01. So

M = z\sqrt{\frac{\pi(1-\pi)}{n}}

0.01 = 2.575\sqrt{\frac{0.5*0.5}{n}}

0.01\sqrt{n} = 2.575*0.5

\sqrt{n} = \frac{2.575*0.5}{0.01}

(\sqrt{n})^2 = (\frac{2.575*0.5}{0.01})^2

n = 16576.6

Rounding up:

A sample of 16577 is required.

8 0
3 years ago
If Bob produces 36 or fewer items in a week, he is paid X dollars per item. If Bob produces more than 36 items in a week, he is
Greeley [361]

Answer:

How many items did Bob produce last week? 32 items.

Step-by-step explanation:

(1) Last week Bob was paid total of $480 for the items that he produced that week.

(2) This week Bob produced 2 items more than last week and was paid a total of $510 for the items that he produced this week.

a) Let's start with the simplest case:  he produced 36 or less items this week.

In this case he produced less than 36 items last week too.

So he was paid the same amount of dollar per item.

Using (1) and (2) assumptions we have:

$480+2X=$510

⇒2X=$510-$480

⇒2X=$30

⇒2X=$30/2

⇒X=$15

He was paid $15 per item.

Last week he was paid $480.

480/15= 32 items.

This week he was paid $510.

510/15=34 items.

The other cases has no solutions.

7 0
3 years ago
PLSS HELP ASAP 100 points + brainlist ONLY EVENS ALL PLSS
BARSIC [14]
Your answer is at the top good luck!
6 0
3 years ago
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