Answer:
#7: Vertex is (2,-6)
y-intercept is (0,6)
#8: Vertex is (-2,-29)
y-intercept is (0,-9)
#9: Vertex is (-1,1)
y-intercept is (0,-5)
#10: Vertex is (2,20)
y-intercept is (0,-8)
Step-by-step explanation:
Graphs are in the picture below
Step-by-step explanation:
The Taylor series expansion is:
Tₙ(x) = ∑ f⁽ⁿ⁾(a) (x − a)ⁿ / n!
f(x) = 1/x, a = 4, and n = 3.
First, find the derivatives.
f⁽⁰⁾(4) = 1/4
f⁽¹⁾(4) = -1/(4)² = -1/16
f⁽²⁾(4) = 2/(4)³ = 1/32
f⁽³⁾(4) = -6/(4)⁴ = -3/128
Therefore:
T₃(x) = 1/4 (x − 4)⁰ / 0! − 1/16 (x − 4)¹ / 1! + 1/32 (x − 4)² / 2! − 3/128 (x − 4)³ / 3!
T₃(x) = 1/4 − 1/16 (x − 4) + 1/64 (x − 4)² − 1/256 (x − 4)³
f(x) = 1/x has a vertical asymptote at x=0 and a horizontal asymptote at y=0. So we can eliminate the top left option. That leaves the other three options, where f(x) is the blue line.
Now we have to determine which green line is T₃(x). The simplest way is to notice that f(x) and T₃(x) intersect at x=4 (which makes sense, since T₃(x) is the Taylor series centered at x=4).
The bottom right graph is the only correct option.
In the given statement above, in this case, the answer would be TRUE. It is true that the inequality x + 2y ≥ 3 is satisfied by point (1, 1). In order to prove this, we just have to plug in the values. 1 + 2(1) <span> ≥ 3
So the result is 1 + 2 </span> ≥ 3. 3 <span> ≥ 3, which makes it true, because it states that it is "more than or equal to", therefore, our answer is true. Hope this answer helps.</span>
Answer:
I got (1,2).
Step-by-step explanation:
Process of elimination:
Multiply the second equation by 3 to get same terms, subtract and solve for Y to get 2.
Plug 2 into second equation for Y to get x=1
(1,2)
Answer:
-23/10 or-2 3/10
Step-by-step explanation:
Convert the decimal number to a fraction by placing the decimal number over a power of ten. Since there is
1
number to the right of the decimal point, place the decimal number over
10
1
(
10
)
. Next, add the whole number to the left of the decimal.
−
2
3
10
