When I leave home to walk to school2And what I think I've seen3Now, what can I say4And I've kept careful track5Just a broken down wagon6When Isay that i saw it on Mulberry St7The story would really be better to hear8A reindeer is better; he's fast and he's fleet9To pull a thing that runs on wheels10Jack or Fred of Joe or NAT-11Say! That makes a story that no one can beat12But he'd look simply grand13If a man sits and listens while hitched on behind14But now what worries me is this...15To guide them through where's traffic's thick-16And he raises his hat as they dash by the stand.17With a roar of its motor an airplane appears18A big magician doing tricks..19For I had a story that NO ONE could beat!20There was so much to tell, I JUST COULDN'T BEGIN!21"Nothing," I said, growing red as a beet
A regular hexagon has sides that are all congruent and angles that all measure 120 degrees. This means the angles of a regular hexagon add up to 720 degrees. ... An irregular hexagon has sides that are not the same measurement and can have points facing inward as well as outward.
30 degrees of the circle which is an acute angle.
To answer the question, you need to determine the amount Mr. Traeger has left to spend, then find the maximum number of outfits that will cost less than that remaining amount.
Spent so far:
... 273.98 + 3×7.23 +42.36 = 338.03
Remaining available funds:
... 500.00 -338.03 = 161.97
The cycling outfits are about $80 (slightly less), and this amount is about $160 (slightly more), which is 2 × $80.
Mr. Traeger can buy two (2) cycling outfits with the remaining money.
_____
The remaining money is 161.97/78.12 = 2.0733 times the cost of a cycling outfit. We're sure he has no interest in purchasing a fraction of an outfit, so he can afford to buy 2 outfits.
Answer:
hey
Step-by-step explanation:
let the age of man be x
400-3x=163
400-163=3x
237/3=x
x= 79
