A and B are postive integers such that 1/a + 1/b +1/ab = 1. Find ab
1 answer:
Answer: ab =6
have:
=> a + b + 1 = ab
⇔ a + b + 1 - ab = 0
⇔ b - 1 - a(b - 1) + 2 = 0
⇔ (b - 1)(1 - a) = -2
because a and b are postive integers => (b - 1) and (1 - a) also are integers
=> (b - 1) ∈ {-1; 1; 2; -2;}
(1 -a) ∈ {-1; 1; 2; -2;}
because (b -1).(1-a) = -2 => we have the table:
b - 1 -1 1 2 -2
1 - a 2 -2 -1 1
a -1 3 2 0
b 0 2 3 -1
a.b 0 6 6 0
because a and b are postive integers
=> (a;b) = (3;2) or (a;b) = (2;3)
=> ab = 6
Step-by-step explanation:
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The roots of the equation , 2+3=m, are non real roots.
The quadratic formula's discriminant is represented by the square root symbol -4ac. If there are two solutions, one solution, or none at all, the discriminant informs us.
As of now, 2m²+3=m we need to find the kind of roots they have.
2m²+3=m
2m²-m+3=0
Here, we can derive the following values from the equation:
a = 2, b = -1, c = 3
An equation's discriminant is stated as:
D = b²-4ac
D = (-1)(-1) - 4(2)(3)
D = 1 - 24
D = -23
Discriminant can determine the kind of roots that the equation contains.
In this instance, the discriminant is below 0.
The equation's roots are complex conjugates when D < 0.
Hence the roots for the equation are non real roots.
To get more information about discriminant follow the link:
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