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vredina [299]
3 years ago
14

The diagram below shows the partial construction of which shape?

Mathematics
2 answers:
Gnom [1K]3 years ago
8 0
If we join all the points where the diameter and the 2 arcs meet the cirsle well have 6 equal lines 
- a regular hexagon

so its a
katovenus [111]3 years ago
6 0
A.) <span>a regular hexagon inscribed in a circle

[ Same arc will be drawn six times,and at the end we'll join the corners,in the end, we get regular hexagon inscribed in a a circle ]

Hope this helps!</span>
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Answer:

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Step-by-step explanation:

f(x) × g(x)

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3 years ago
Rewrite in simplest radical form: x^4/5 / x^1/3 into a√x^b
mrs_skeptik [129]

Answer:

\sqrt[15]{x^7}

Step-by-step explanation:

If we have the expression

\frac{x^{\frac{4}{5}}}{x^{\frac{1}{3}}}, we have to think about exponent rules.

If we have a^b \div a^c, then the value will be equal to a^{b-c}.

So \frac{x^{\frac{4}{5}}}{x^{\frac{1}{3}}} simplified will be x^{\frac{4}{5} - \frac{1}{3}}

Converting \frac{4}{5} and \frac{1}{3} into fifteenths (lcm) gets us \frac{12}{15} - \frac{5}{15} = \frac{7}{15}.

We can convert x^{\frac{7}{15}} into a radical by taking the denominator root of x to the numerator.

\sqrt[15]{x^7}.

Hope this helped!

6 0
3 years ago
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Vera_Pavlovna [14]

Answer:

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Step-by-step explanation:

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