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3 years ago

Name:

Mathematics

2 answers:

Elanso [62]3 years ago

8 0

Answer:

24.25 years

Step-by-step explanation:

We know that average of a set = (sum of all terms) / (number of terms). Right now, we know two things: the average of the set (21 years) and the number of terms in the set (5). Therefore, we can rewrite the equation to solve for the sum of all terms.

We have: 21 = $\frac{sum}{5}$

sum = 21 · 5 = 105

Now we know the sum of ages of the 5 girls. We want to find the average age of the 4 remaining girls when we take out the girl who is 8 years old. As previously stated, to find the average of a set, we need to know two things: the sum of all terms in the set and the number of terms in the set. Right now, we only know one of those things: the number of terms in the set, which is 4. To find the sum, we can simply subtract the 8-year-old girl's age from the sum of ages of the 5 girls, which would be 105 - 8 = 97.

Therefore, the average age of the 4 remaining girls is $\frac{97}{4} = 24.25$ years.

Hope this helps!

Svetllana [295]3 years ago

3 0

Answer:

24.25

Step-by-step explanation:

Since the average of 5 girls is 21, there total age is 105 (21*5)

If one of them is 8, 105-8 is 97 and 97/4 (because there is 4 girls left) is 24.25

Hope this helps you!

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frutty [35]

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3 years ago

Five companies (A, B, C, D, and E) that make elec- trical relays compete each year to be the sole sup- plier of relays to a majo

NNADVOKAT [17]

Answer:

$P(a | e') = 0.22$

$P(b | e') = 0.28$

$P(c | e') = 0.33$

$P(a | e' , d' , b') = 0.57$

Step-by-step explanation:

From the question we are told that

The probabilities are

Supplier chosen A B C

Probability P(a) = 0.20 P(b) = 0.25 P(c) = 0.15

D E

P(d) = 0.30 P(e) = 0.10

Generally the new probability of companies A being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(a | e') = \frac{P (a \ and \ e')}{P(e')}$

$P(a | e') = \frac{P (a)}{P(e')}$

$P(a | e') = \frac{P (a)}{1- P(e)}$

=> $P(a | e') = \frac{ 0.20}{1- 0.10}$

=> $P(a | e') = 0.22$

Generally the new probability of companies B being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(b | e') = \frac{P (b \ and \ e')}{P(e')}$

$P(b | e') = \frac{P (b)}{P(e')}$

$P(b | e') = \frac{P (b)}{1- P(e)}$

=> $P(b | e') = \frac{ 0.25}{1- 0.10}$

=> $P(b | e') = 0.28$

Generally the new probability of companies C being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(c | e') = \frac{P (c \ and \ e')}{P(e')}$

$P(c | e') = \frac{P (c)}{P(e')}$

$P(c | e') = \frac{P (c)}{1- P(e)}$

=> $P(c | e') = \frac{ 0.15}{1- 0.10}$

=> $P(c | e') = 0.17$

Generally the new probability of companies D being chosen as the sole supplier this year given that supplier E goes out of business is mathematically represented as below according to Bayes theorem

$P(d | e') = \frac{P (d \ and \ e')}{P(e')}$