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NARA [144]
3 years ago
5

(3ײ+5y²)³= (2y³-×5)²=

Mathematics
1 answer:
irakobra [83]3 years ago
7 0
First one:
(3x^2+5y^2)^3
Step 1: Use the binomial theorem to expand
(3x^2)+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)2+(5y^2)^3
Step 2: Simplify each term
27(x^2)^3+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
Step 3: Multiply the exponents
27x^6+27x^4(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
27x^5+135x^4y^2+3(3x^2)(5y^2)^2+(5y^2)^3
Keep going to get the final answer:
27x^6+135x^4y^2+225x^2y^4+125y^6

2nd question: (2y^3-5x)^2
Do the same thing...step by step
Answer: 4y^6-20xy^3+25x^2
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3 years ago
2. Find mzR and mzS.<br> 89°<br> R<br> 157 T<br> Р
baherus [9]

Answer:

m∠R = 123°

m∠S = 91°

Step-by-step explanation:

The measure of an inscribed angle is 1/2 the measure of the intercepted arc

m of arc QRS = 2 m∠P = 2(57) = 114

Now m of arc SPQ = 360 - 114 = 246

So, m∠R = 1/2(246) = 123

m of arc RSP = 2 m∠Q = 2(89) = 178

m of arc PQR = 360 - 178 = 182

m∠S = 1/2(182) = 91

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3 years ago
The side of a square is 3 and 5/2 inches
Murrr4er [49]
Perimeter=22 inches
Area=121/4 inches
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3 years ago
Solve this and help me plsss​
alexandr402 [8]

Answer:

x = 2

Step-by-step explanation:

(x² logₓ27) log₉x = x + 4

Use change of base formula.

x² (log 27 / log x) (log x / log 9) = x + 4

Simplify.

x² (log 27 / log 9) = x + 4

x² (log 3³ / log 3²) = x + 4

x² (3 log 3 / (2 log 3)) = x + 4

x² (3 / 2) = x + 4

3x² = 2x + 8

3x² − 2x − 8 = 0

(x − 2) (3x + 4) = 0

x = 2 or -4/3

Since x > 0, x = 2.

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