First one: (3x^2+5y^2)^3 Step 1: Use the binomial theorem to expand (3x^2)+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)2+(5y^2)^3 Step 2: Simplify each term 27(x^2)^3+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3 Step 3: Multiply the exponents 27x^6+27x^4(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3 27x^5+135x^4y^2+3(3x^2)(5y^2)^2+(5y^2)^3 Keep going to get the final answer: 27x^6+135x^4y^2+225x^2y^4+125y^6
2nd question: (2y^3-5x)^2 Do the same thing...step by step Answer: 4y^6-20xy^3+25x^2
