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3 years ago

(3×²+5y²)³= (2y³-×5)²=

1 answer:

7 0

First one:
(3x^2+5y^2)^3
Step 1: Use the binomial theorem to expand
(3x^2)+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)2+(5y^2)^3
Step 2: Simplify each term
27(x^2)^3+3(3x^2)^2(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
Step 3: Multiply the exponents
27x^6+27x^4(5y^2)+3(3x^2)(5y^2)^2+(5y^2)^3
27x^5+135x^4y^2+3(3x^2)(5y^2)^2+(5y^2)^3
Keep going to get the final answer:
27x^6+135x^4y^2+225x^2y^4+125y^6

2nd question: (2y^3-5x)^2
Do the same thing...step by step
Answer: 4y^6-20xy^3+25x^2

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Simplify this expression;<br>3(2x+7)

Advocard [28]

Answer:

6x+21 (Maybe)

Are you doing the buddy method, how is your teacher wanting to do this, When you respond I might have the correct answer

(buddy method) Multiply the 2x and 7 by the 3 giving you 6x+21 and then that's it you cant do anything else but I don't know if that's how you're teacher wants it done.

5 0

3 years ago

Read 2 more answers

1. y = x2 + 8x + 15<br> Find the zeros of the function by rewriting the function in intercept form

lubasha [3.4K]

The zeros of given function $y=x^{2}+8 x+15$ is – 5 and – 3

<u>Solution:</u>

$\text { Given, equation is } y=x^{2}+8 x+15$

We have to find the zeros of the function by rewriting the function in intercept form.

By using intercept form, we can put value of y as to obtain zeros of function

We know that, intercept form of above equation is $x^{2}+8 x+15=0$

$\text { Splitting } 8 x \text { as }(5+3) x \text { and } 15 \text { as } 5 \times 3$

$\begin{array}{l}{\rightarrow x^{2}+(5+3) x+5 \times 3=0} \\\\ {\rightarrow x^{2}+5 x+3 x+5 \times 3=0}\end{array}$

Taking “x” as common from first two terms and “3” as common from last two terms

x (x + 5) + 3(x + 5) = 0

(x + 5)(x + 3) = 0

Equating to 0 we get,

x + 5 = 0 or x + 3 = 0

x = - 5 or – 3

Hence, the zeroes of the given function are – 5 and – 3

5 0

3 years ago

HELP MATH THIS IS DUE SOON

Oxana [17]

Answer:

600

Step-by-step explanation:

36 times 18=648 but u need to add o the nearest hundred

4 0

2 years ago

Read 2 more answers

A cup of raw Arborio rice weighs 7 ounces. One cup will serve 1 people. Arborio rice is purchased in 2-pound boxes for $1.99. Ho

kow [346]

The rice will cost $17.6 for serving 40 people

<h3><u>Solution:</u></h3>

We need to determine the cost of serving 40 people with rice

Arborio rice is purchased in 2-pound boxes for $1.99

The price of 1 pound box will be $\frac{\$ 1.99}{2}=\$ 0.995$

1 Pound (lb) is equal to 16 ounces (oz)

Therefore, the price of 16 ounces is $0.995

A cup of raw Arborio rice weighs 7 ounces and it serve 1 people

$\begin{array}{l}{\text { The cost per person is } \frac{\$ 0.995}{16} \times 7=\$ 0.44} \\\\ {\text { The cost for serving } 40 \text { people }=\$ 0.44 \times 40=\$ 17.6}\end{array}$

Therefore rice will cost $17.6 for serving 40 people

7 0

3 years ago

What is the square root of 5

Zigmanuir [339]

Answer:

2.236

Step-by-step explanation:

you could estimate it to be between 2 and 3 (because 5 is between 4 and 9)

or you just put it into a calculator

5 0

3 years ago