Answer:
0.001 and 1/1000
Step-by-step explanation:
Answer: He has enough bottle
Step-by-step explanation:
From the question, we are informed that Craig has 5/6 of a bottle of glue and that a recipe calls for three quarters of a bottle.
To know if he has enough bottle, we can subtract 3/4 from 5/6. This will be:
= 5/6 - 3/4
= 10/12 - 9/12
= 1/12
He has enough bottle since we got a positive value when we subtracted.
Answer:
3: ![a^{2}+2ab+b^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2B2ab%2Bb%5E%7B2%7D)
4: ![8x^{3} -12x^{2}+6x-1](https://tex.z-dn.net/?f=8x%5E%7B3%7D%20-12x%5E%7B2%7D%2B6x-1)
Step-by-step explanation:
Question 3 can be re-written as:
![(a+b)(a+b)](https://tex.z-dn.net/?f=%28a%2Bb%29%28a%2Bb%29)
which equals:
![a^{2}+2ab+b^{2}](https://tex.z-dn.net/?f=a%5E%7B2%7D%2B2ab%2Bb%5E%7B2%7D)
Question 4 can be re-written as:
![(2x-1)(2x-1)(2x-1)](https://tex.z-dn.net/?f=%282x-1%29%282x-1%29%282x-1%29)
Doing the first 2 brackets gives us:
![(4x^{2} -4x+1)(2x-1)](https://tex.z-dn.net/?f=%284x%5E%7B2%7D%20-4x%2B1%29%282x-1%29)
Expanding these two:
![8x^{3} -4x^{2} -8x^{2} +4x+2x-1](https://tex.z-dn.net/?f=8x%5E%7B3%7D%20-4x%5E%7B2%7D%20-8x%5E%7B2%7D%20%2B4x%2B2x-1)
Simplifying it:
![8x^{3} -12x^{2}+6x-1](https://tex.z-dn.net/?f=8x%5E%7B3%7D%20-12x%5E%7B2%7D%2B6x-1)
63 i hope this helps if not tell me
V= a^3
So in this case V= 6^3
V= 216