The boiling point of oxygen is higher than nitrogen's boiling
The reason the boiling point of O2 is higher is not because of increased van der Waals interactions, but simple physics. The mass of a molecule of O2 is greater than that of a molecule of N2, so the molecule of O2 traveling at a speed sufficient to break out of the liquid phase has a greater kinetic energy than an analogous N2 molecule.
The net effect is that more energy must be distributed throughout a sample of O2 to achieve a given vapor pressure (in this case equal to atmospheric pressure) than for a sample of N2. More energy means greater temperature.
Answer:
Liquid
Explanation:
had this ln a test and got it right
You may find the electron diagram of ammonia and the ammonium ion in the attached picture.
Explanation:
Ammonia NH₃ have covalent bonds with the hydrogen atoms in which for each bond one electron comes from nitrogen atom (blue dot) and the other from the hydrogen atom (red dot). You may see that the nitrogen remains with the lone pair of electrons that does not participate in bonding.
Ammonia NH₃ have a basic character and is able to accept a proton H⁺ from an acid to form the ammonium ion NH₄⁺. The fourth bond formed its called a coordinative-covalent bond that is created only with the nitrogen lone pair of electrons (blue dots).
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ammonium ion
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the balanced equation for the formation of water is as follows
2H₂ + O₂ ---> 2H₂O
molar ratio of oxygen to water is 1:2
mass of water produced is - 46 g
therefore the number of moles of water produced - 46 g / 18 g/mol = 2.56 mol
1 mol of oxygen reacts to give 2 mol of water assuming oxygen is the limiting reactant
for 2 mol of water to be produced 1 mol of oxygen has to react
therefore for 2.56 mol of water to be produced - 1/2 x 2.56 mol = 1.28 mol of oxygen should react
mass of oxygen reacted is - 1.28 mol x 32 g/mol = 41.0 g
mass of oxygen that should react is 41 g
