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RUDIKE [14]
4 years ago
13

Write the dissociation reaction and the corresponding ka equilibrium expression for hcn in water

Chemistry
1 answer:
Stells [14]4 years ago
7 0
Chemical reaction: HCN(aq) + H₂O(l) ⇄ CN⁻(aq) + H₃O⁺(aq)<span>.
</span>Ka = [CN⁻] · [H₃O⁺] / [HCN].
[HCN] is equilibrium concentration of hydrocyanic acid.
hydrocyanic acid is weakly acidic and <span>partially </span>ionizes<span> in water solution and give the </span>cyanide anion (CN⁻).
The salts<span> of the cyanide anion are called cyanides.</span>
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