Question

Find the distance between C(-8,-5) and D(-2,3). Find the midpoint of CD.

Answer 1

Answer:

10 units and (- 5, - 1 )

Step-by-step explanation:

Calculate the distance d using the distance formula

d = $\sqrt{(x_{2}-x_{1})^2+(y_{2}-y_{1})^2 }$

with (x₁, y₁ ) = C(- 8, - 5) and (x₂, y₂ ) = D(- 2, 3)

d = $\sqrt{(-2+8)^2+(3+5)^2}$

   = $\sqrt{6^2+8^2}$

   = $\sqrt{36+64}$

    = $\sqrt{100}$

    = 10

Calculate the midpoint using the midpoint formula

( $\frac{x_{1}+x_{2} }{2}$, $\frac{y_{1}+y_{2} }{2}$ )

= $\frac{-8-2}{2}$, $\frac{-5+3}{2}$ )

= $\frac{-10}{2}$, $\frac{-2}{2}$ )

= (- 5, - 1 )