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mrs_skeptik [129]
3 years ago
11

if you have a class with 32 students and 16 of them are boys how many girls are there in the class ​

Mathematics
1 answer:
MA_775_DIABLO [31]3 years ago
6 0

Answer: if there are 32 students in the class and 16 are boys so the other half well be 16 girls. 16 + 16 = 32. Sooo the answer is 16 girls

Step-by-step explanation:

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Given an x intercept of 7 and no y intercept, write the equation.
Elena-2011 [213]

m=y+7x, or m=7x+y, it is correct either way you would write it.

3 0
3 years ago
Jorge bought a crate of floor tiles for 95.94 the crate had 6 boxes of floor tiles each box contained 20 floor tiles
geniusboy [140]
The answer is 

6 boxes x 20 tiles/box = 120 tiles

Price was $95.94

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7 0
3 years ago
If sin θ = 1/2 , then find the value of (sin 3 θ)/(1+ cos 2 θ)<br>​
Ipatiy [6.2K]

<u>EXPLANATION</u><u>:</u>

Given that

sin θ = 1/2

We know that

sin 3θ = 3 sin θ - 4 sin³ θ

⇛sin 3θ = 3(1/2)-4(1/2)³

⇛sin 3θ = (3/2)-4(1/8)

⇛sin 3θ = (3/2)-(4/8)

⇛sin 3θ = (3/2)-(1/2)

⇛sin 3θ = (3-1)/2

⇛sin 3θ = 2/2

⇛sin 3θ = 1

and

cos 2θ = cos² θ - sin² θ

⇛cos 2θ = 1 - sin² θ - sin² θ

⇛cos 2θ = 1 - 2 sin² θ

Now,

cos 2θ = 1-2(1/2)²

⇛cos 2θ = 1-2(1/4)

⇛cos 2θ = 1-(2/4)

⇛cos 2θ = 1-(1/2)

⇛cos 2θ = (2-1)/2

⇛cos 2θ = 1/2

Now,

The value of sin 3θ /(1+cos 2θ

⇛1/{1+(1/2)}

⇛1/{(2+1)/2}

⇛1/(3/2)

⇛1×(2/3)

⇛(1×2)/3

⇛2/3

<u>Answer</u> : Hence, the req value of sin 3θ /(1+cos 2θ) is 2/3.

<u>also</u><u> read</u><u> similar</u><u> questions</u><u>:</u> If sin Θ = 2/3 and tan Θ < 0, what is the value of cos Θ?

brainly.com/question/12618768?referrer

if cos θ -sin θ =1, find θ cos θ +sin θ?

brainly.com/question/88125?referrer

7 0
3 years ago
Find the distance between the points (–10,3) and (–2,3).
nikdorinn [45]

Answer:

8

Step-by-step explanation:

10 - 2

7 0
3 years ago
c) The probability is 1% that an electrical connector that is kept dry fails during the warranty period of a portable computer.
Anni [7]

Answer: There is 0.014 proportion of connectors fail during the warranty period.

Step-by-step explanation:

Let A be the event that connector fails.

Let B be the event that connector wet.

P(B) = 10%

P(B') = 90%

P(A|B) = 0.05

P(A|B') = 0.01

So, we need to find the proportion of connectors fail during the warranty period is given by

P(A)=P(B)P(A|B)+P(B')P(A|B')\\\\P(A)=0.1\times 0.05+0.9\times 0.01\\\\P(A)=0.014

Hence, there is 0.014 proportion of connectors fail during the warranty period.

3 0
3 years ago
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