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Llana [10]
3 years ago
9

While doing back to school shopping on tax-free weekend, Mrs. Michaels bought 2 packs of mechanical pencils and 3 binders for a

total cost of $21.00. Mr. Lawrence bought 5 of the same packs of mechanical pencils and 2 of the same binders for a total of $25.00. How much does each pack of pencils cost? *
Mathematics
1 answer:
IRISSAK [1]3 years ago
4 0

Answer:

$3.00  

Step-by-step explanation:

Let p = the cost of a pack of pencils

and b = the cost of a binder

Then we have two simultaneous equations.

(1)  2p + 3b  = 21.00

(2) 5p + 2b = 25.00

1. Multiply each equation by numbers to give one of the variables the same coefficient.

Multiply (1) by 2 and (2) by 3.This gives

(3)  4p + 6b = 42.00

(4) 15p + 6b = 75.00

2. Subtract (3) from (4)

This gives

(5) 11p = 33.00

3. Solve equation (5) for p

Divide each side by 11

p = 3.00

Each pack of pencils costs $3.00.

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What expression is equivalent to 4x^4+4x^2-45
Marysya12 [62]

Answer: 227

Step-by-step explanation:

4x^4 = (4*4*4*4)  256

4x^2 = (4*4)   16

256 + 16= 272

272 - 45 = 227

5 0
3 years ago
The entry fee at a small fair is $1.50 for children and $4.00 for adults. On a certain day, 2200 people enter the fair and $5000
Sauron [17]

Answer:

The number of children attended the fair is 1520.

Step-by-step explanation:

We are given the following in the question:

Entry fee foe children = $1.50

Entry fee foe adult = $4.00

Total number of people in fair = 2200

Total money collected = $5000

Let x be the number of children and y be the number of adults in the fair.

Then, we can write the following equations:

x + y = 2200\\1.5x + 4y = 5000

Solving the two equations, we have:

1.5x + 1.5y = 3300\\1.5x + 4y = 5000\\\Rightarrow 2.5y = 1700\\y = 680\\x = 2200-680 = 1520

Thus, there were 1520 children and 680 adults in the fair.

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bija089 [108]

You can solve a system using substitution, elimination, or graphing method.

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3 years ago
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