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qaws [65]
3 years ago
13

A produção mensal de uma Olaria é de 5.000 tijolos nesse mês alvará produziu 3925 tijolos quantos tijolos ainda falta para compl

etar a produção mensal
Mathematics
1 answer:
Gnesinka [82]3 years ago
5 0

Responda:

1075 tijolos

Explicação passo a passo:

Dado que:

Número de tijolos produzidos Mensalmente = 5.000 tijolos

A quantidade de tijolos produzidos por licença = 3925

O número de tijolos que ainda faltam no valor mensal desejado:

Quantidade de produção mensal - quantidade produzida por licença

5000 - 3925 = 1075 tijolos

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john earns $67.5
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What is the surface area of this triangular pyramid?
lidiya [134]

<em>48.25 in^2</em>

Step-by-step explanation:

The formula for the surface area of a pyramid is:

SA=B+\frac{1}{2}l(number of base sides)(b)

B represents the area of the base, which in this case is a triangle. We will figure out the area of the base first, using the formula for the area of a triangle.

A=\frac{1}{2}bh

A=.5*5*4.3

A = 10.75

Now we can plug in 10.75 for B.

SA=10.75+.5*5*3*5

The cursive L will be the lateral height, which is 5. Since there are 3 sides on the base we can put that in for the number of base sides, and the base is 5.

SA=

48.25 in^2

8 0
3 years ago
With a capacity of 6,300 people, Royal Caribbean’s Oasis of the Seas is the world’s largest cruise ship. The average beer consum
Mariulka [41]

Step-by-step explanation:

Mean = 81740

Standard deviation = 4590

Sample size = 15

Alpha level = 1-0.95 = 0.05

Df = 15-1 = 14

Critical value:

alpha/2 = 0.05/2 = 0.05

t0.025

t critical value = 2.145

Margin of error ME

2.145 x 4590/√15

2.145 x 4590/3.873

ME = 2542.09

Confidence interval

Lower CI = mean - ME

= 81740-2542.09

= 79197.91

Upper CI = mean + ME

= 81740+2542.09

= 84282.09

[ 79197.91, 84282.09]

B.

Using excel, exact answer for CI

Lower limit = 79198.142724212173

Upper limit = 84281.8572757827

C.

The assumptions to be made from the population are that

1. Samples are random

2. These samples are gotten from an approximately normal distribution

6 0
3 years ago
Consider the figure below. Line FG is parallel to line JK.
Svet_ta [14]

Answer:

A. a = 10

B. m<FNT = 120°

C. m<KTU = 60°

Step-by-step explanation:

A. (7a + 50)° and (14a - 20)° are corresponding angles. Therefore:

(7a + 50)° = (14a - 20)°

Use this equation to find the value of a

7a + 50 = 14a - 20

Combine like terms

7a - 14a = - 50 - 20

-7a = -70

Divide both sides by -7

-7a/-7 = -70/-7

a = 10

B. m<FNT = (14a - 20)° (alternate interior angles are congruent)

Plug in the value of a

m<FNT = 14(10) - 20

m<FNT = 140 - 20

m<FNT = 120°

C. m<KTU + (14a - 20)° = 180° (linear pair)

Plug in the value of a

m<KTU + 14(10) - 20 = 180

m<KTU + 120 = 180

m<KTU + 120 - 120 = 180 - 120

m<KTU = 60°

6 0
3 years ago
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