Answer:
![\boxed{y=4x^3-x^2-50x+25}](https://tex.z-dn.net/?f=%5Cboxed%7By%3D4x%5E3-x%5E2-50x%2B25%7D)
Step-by-step explanation:
The given function is
![y=(x-5)(x+5)(2x-1)](https://tex.z-dn.net/?f=y%3D%28x-5%29%28x%2B5%29%282x-1%29)
Observe that, the first two factors are from difference of two squares.
![\Rightarrow y=(x^2-5^2)(2x-1)](https://tex.z-dn.net/?f=%5CRightarrow%20y%3D%28x%5E2-5%5E2%29%282x-1%29)
![\Rightarrow y=(x^2-25)(2x-1)](https://tex.z-dn.net/?f=%5CRightarrow%20y%3D%28x%5E2-25%29%282x-1%29)
We expand the brackets using the distributive property to obtain;
![\Rightarrow y=2x^2(2x-1)-25(2x-1)](https://tex.z-dn.net/?f=%5CRightarrow%20y%3D2x%5E2%282x-1%29-25%282x-1%29)
![\Rightarrow y=4x^3-x^2-50x+25](https://tex.z-dn.net/?f=%5CRightarrow%20y%3D4x%5E3-x%5E2-50x%2B25)
The above function is now in standard form, since the terms are arranged in descending powers of
.
Given :
Total amount of pudding made, T = 5 pounds.
Size of each cup, s = 4 ounces.
To Find :
How many total individual pudding cups can Harper make.
Solution :
Let, n number of pudding cups can filled with 5 pounds pudding.
We know, 1 pound = 16 ounces.
So, 5 pounds = 16×5 = 80 ounces.
Now,
![n = \dfrac{80}{s}\\\\n = \dfrac{80}{4}\\\\n = 20 \ cups](https://tex.z-dn.net/?f=n%20%3D%20%5Cdfrac%7B80%7D%7Bs%7D%5C%5C%5C%5Cn%20%3D%20%5Cdfrac%7B80%7D%7B4%7D%5C%5C%5C%5Cn%20%3D%2020%20%5C%20cups)
Therefore, 20 cups can be filled with 5 pounds of pudding.
Answer:
44
Step-by-step explanation:
im pretty sure its 44. half of the area is 22, and the other halfs area is the same size meaning its also 22. so just add those together and u get 44!
Step-by-step explanation:
0.075 % is the probability of that