Step-by-step explanation:
take the base square. find the diagonal
16^2+16^2 = 2*16^2= d^2
d= 16√2
half of the diagonal will form the baSe of right triangle of hypotenuse 10. but the base will be 8√2 which is greater than 10. so I feel the slant hr has to be different and more than 10
first get all variables on the same side, then use elimination to solve.
x = -3
y = -11
Answer:
NOT a solution
Step-by-step explanation:
Substitute the values of x and y and see if the equation is satisfied:
3(1) -7(-1) = 3 +7 = 10 ≠ 4 . . . . . . the given point is not on the line
(1, -1) is not a solution to the equation.
_____
(-1, 1) is a solution
Answer:
5
Step-by-step explanation:
Plug in x = 2 into the equation 2x + 1
2x + 1
2 * 2 + 1
4 + 1
5
So, we know the center is at -3,-1, ok
hmmm what's the radius anyway? well, we know that there's a point at 1,2 that is on the circle's path...hmmmm what's the distance from the center to that point? well, is the radius, let's check then.
so, what's the equation of a circle with center at -3, -1 and a radius of 5?