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3 years ago

La ecuación de la recta que lasa a través de los puntos P1 (2,5) y P2 (4,11) es: a) 3x+y+1=0 b)3x-y-1=0 c) 3x-y+1=0

Mathematics

1 answer:

Zolol [24]3 years ago

5 0

Respuesta:

3x-y-1 = 0

Explicación paso a paso:

La forma estándar de ecuación de una línea se expresa como y = mx + b

M es la pendiente

b es la intersección con el eje y

Dada la coordenada P1 (2,5) y P2 (4,11)

Pendiente m = y2-y1 / x2-x1

m = 11-5 / 4-2

m = 6/2

m = 3

Sustituya m = 3 y (2,5) en y = mx + b

5 = 3 (2) + b

5 = 6 + b

b = 5-6

b = -1

Obtén la ecuación

y = 3x-1

Igualar a cero

y - 3x +1 = 0

Multiplicar por -1

3x-y-1 = 0

Esto da la ecuación requerida

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<h2>{ Pisces04 }</h2>

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