5ab/5b= a
-10b^2/5b= -2b
15bc/5b= 3c
Put it all together
Final answer: a-2b+3c
Answer:
Here is a generic way to set up this type of algebra problem.
d = total amount of dirt at the site (tons)
r = rate or removal (tons/hr)
t = time it takes to remove all of the dirt (hr)
d = rt
The total amount of dirt equals the removal rate times hours spent removing all the dirt.
Since you want to solve for t, divide both sides by r
t = d/r
DC/AC=EC/BC
x/(x+3)=10/16
10(x+3)=16x
10x+30=16x
30=6x
x=5
DC=x=5
DC=5 units long
10/16=DE/AB, DE=y
10/16=y/10
16*y=10*10
y=6.25≈6.3
DE≈6.3
Answer:
Rs 600,000
Step-by-step explanation:
Let the original amount be X
Amount given to daughter = (1/2) X = X/2
Amount given to son = (1/3) X = X/3
donation = Rs 100,000
Total amount = Amount Given to Daughter + Amount given to Son + Donation
X = X/2 + X/3 + 100,000 (solve for X)
X = (5/6)X + 100,000
X - (5/6)X = 100,000
(1/6)X = 100,000
X = (6) (100,000)
x = Rs 600,000
Answer:
4
Step-by-step explanation:
9 times 4 = 36 and 36-10= 26
26 times two is 52
3 times 4 is 12
12 times two is 24
52+24= 76
