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3 years ago

What is 3x+5y=40 in slope intercept form

Mathematics

1 answer:

cupoosta [38]3 years ago

3 0

Hey, hope you're doing great today :)

Let's learn about what we need to learn to solve our equation.

We need to make this into a y=mx+b form.

That's the main thing you need to understand while doing this.

Now let's get onto the problem!

This is to much big of an equation to set up, so we need to change some things up.

We need to make one thing into a fraction.

It should look like y = -3/5x + 8.

This is in correct y = mx + b form.

Hopefully that clears things up :)

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Which of the following can you determine, when you use deduction and start from a given set of rules and conditions? O A. What m

snow_tiger [21]

Answer:

Its C it must be true

Step-by-step explanation:

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2 years ago

$10.40 to $13.12 is simplify your answer

Bumek [7]

The required simplified value of $10.40 to $13.12 is $2.72.

Given that,
To determine the simplified value of $10.40 to $13.12.

<h3>What is simplification?</h3>

The process in mathematics to operate and interpret the function to make the function or expression simple or more understandable is called simplifying and the process is called simplification.

Here,
In the question, asked about the difference between the numbers
$10.40 to $13.12
= 13.12 - 10.40
= $2.72

Thus, the required simplified value of $10.40 to $13.12 is $2.72.

Learn more about simplification here:
brainly.com/question/12501526

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4 0

2 years ago

The amount of lateral expansion (mils) was determined for a sample of n = 8 pulsed-power gas metal arc welds used in LNG ship co

Alona [7]

Answer:

95% Confidence interval for the variance:

$3.6511\leq \sigma^2\leq 34.5972$

95% Confidence interval for the standard deviation:

$1.9108\leq \sigma \leq 5.8819$

Step-by-step explanation:

We have to calculate a 95% confidence interval for the standard deviation σ and the variance σ².

The sample, of size n=8, has a standard deviation of s=2.89 miles.

Then, the variance of the sample is

$s^2=2.89^2=8.3521$

The confidence interval for the variance is:

$\dfrac{ (n - 1) s^2}{ \chi_{\alpha/2}^2} \leq \sigma^2 \leq \dfrac{ (n - 1) s^2}{\chi_{1-\alpha/2}^2}$

The critical values for the Chi-square distribution for a 95% confidence (α=0.05) interval are:

$\chi_{0.025}=1.6899\\\\\chi_{0.975}=16.0128$

Then, the confidence interval can be calculated as:

$\dfrac{ (8 - 1) 8.3521}{ 16.0128} \leq \sigma^2 \leq \dfrac{ (8 - 1) 8.3521}{1.6899}\\\\\\3.6511\leq \sigma^2\leq 34.5972$

If we calculate the square root for each bound we will have the confidence interval for the standard deviation:

$\sqrt{3.6511}\leq \sigma\leq \sqrt{34.5972}\\\\\\1.9108\leq \sigma \leq 5.8819$

6 0

3 years ago

According to the line plot how many apples weigh 5/8 of a pound

atroni [7]

Answer:

Answer:4 apples weigh 5/8 pound.

Step-by-step explanation:

3 0

3 years ago

Read 2 more answers

Solve 4 square root of 3 = 8cos

sukhopar [10]

Therefore $\theta = 30^\circ$

Step-by-step explanation:

Given,

$4\sqrt{3 } =8 cos \theta$

$\Leftrightarrow cos \theta =\frac{4\sqrt{3} }{8}$

$\Leftrightarrow cos \theta =\frac{\sqrt{3} }{2}$

$\Leftrightarrow cos \theta =cos 30^\circ$

$\Leftrightarrow \theta = 30^\circ$

Therefore $\theta = 30^\circ$

4 0

3 years ago