3x - 3y + 9 = 0
The y-intercept is the point on the graph where it crosses the y-axis, and has coordinates of (0, b). It is also the value of y when x = 0.
To solve for the y-intercept, set x = 0:
3(0) - 3y + 9 = 0
3(0) - 3y + 9 = 0
Subtract 9 from both sides:
- 3y + 9 - 9 = 0 - 9
- 3y = -9
Divide both sides by -3 to solve for y:
-3y/-3 = -9/-3
y = 3
Therefore, the y-intercept is (0, 3).
The x-intercept is the point on the graph where it crosses the x-axis, and has coordinates of (a, 0). It is also the value of x when y = 0.
To solve for the x-intercept, set y = 0:
3x - 3(0)+ 9 = 0
3x -0 + 9 = 0
Subtract 9 from both sides:
3x + 9 - 9 = 0 - 9
3x = -9
Divide both sides by 3 to solve for x:
3x/3 = -9/3
x = -3
Therefore, the x-intercept is (-3,0).
The correct answers are:
Y-intercept = (0, 3)
X-intercept = (-3, 0)
A and b are both accurate
For a:
which is true
For b:
which is also true
8+(9t+4)
remove ( )
since there's a + in front of the ( ) the value will not change
8+9t+4
combine like terms
9t+12
Hope this helps
Answer:
what grade are you in so then I could get the answer
