3 years ago

The GCF of 148 is what ?

Mathematics

2 answers:

posledela3 years ago

8 0

To find the gcf you need two numbers

bonufazy [111]3 years ago

8 0

You will need two numbers to find the GCF.

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How to find area of a square room if it's length is 5cm

alina1380 [7]

Answer:

150 cm²

Step-by-step explanation:

Since the room is square, assuming that it is a cube, the area will be 6s², where s is the side length.

Given a side length of 5cm, the area is

6(5)² = 6cm × 25cm = 150cm²

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3 years ago

The difference between a number and 12 is 20 in a fraction

soldi70 [24.7K]

Do you want us to simplify? If so, it would be 3/5

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3 years ago

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mestny [16]

Answer:

187 units²

Step-by-step explanation:

break the figure into two rectangles

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3 years ago

Consider the system of differential equations dxdt=−4ydydt=−4x. Convert this system to a second order differential equation in y

koban [17]

$\dfrac{\mathrm dy}{\mathrm dt}=-4x\implies x=-\dfrac14\dfrac{\mathrm dy}{\mathrm dt}\implies\dfrac{\mathrm dx}{\mathrm dt}=-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}$

Substituting this into the other ODE gives

$-\dfrac14\dfrac{\mathrm d^2y}{\mathrm dt^2}=-4y\implies y''-16y=0$

Since $x(t)=-\dfrac14y'(t)$ , it follows that $x(0)=-\dfrac14y'(0)=4\implies y'(0)=-16$ . The ODE in $y$ has characteristic equation

$r^2-16=0$

with roots $r=\pm4$ , admitting the characteristic solution

$y_c=C_1e^{4t}+C_2e^{-4t}$

From the initial conditions we get

$y(0)=5\implies 5=C_1+C_2$

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So we have

$\boxed{y(t)=\dfrac12e^{4t}+\dfrac92e^{-4t}}$

Take the derivative and multiply it by -1/4 to get the solution for $x(t)$ :

$-\dfrac14y'(t)=\boxed{x(t)=-\dfrac12e^{4t}+\dfrac92e^{-4t}}$

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4 years ago

M is the midpoint of C(1,7) and D(-8,-3). Find the coordinates of M.

Alex73 [517]

Answer:

hello I hope the image helps

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1 year ago