Answer: a) 0.0792 b) 0.264
Step-by-step explanation:
Let Event D = Families own a dog .
Event C = families own a cat .
Given : Probability that families own a dog : P(D)=0.36
Probability that families own a dog also own a cat : P(C|D)=0.22
Probability that families own a cat : P(C)= 0.30
a) Formula to find conditional probability :
(1)
Similarly ,
Hence, the probability that a randomly selected family owns both a dog and a cat : 0.0792
b) Again, using (2)
Hence, the conditional probability that a randomly selected family owns a dog given that it owns a cat = 0.264
Answer:
(-4, 2)
Step-by-step explanation:
4x+2y=-12
3x+y=-10
Start by dividing the first equation by 2 to simplify it...
2x+y=-6
Then, subtract -2x from both sides to isolate y...
y=-2x-6
Substitute -2x-6 for y in the second equation...
3x-2x-6=-10
Combine like terms...
x-6=-10
Add 6 to both sides
x-6+6=-10+6
x=-4
Plug -4 in for x to solve for y:
3(-4)+y=-10
-12+y=-10
Add 12 to both sides
-12+12+y=-10+12
y=2
(x,y)=(-4,2)
Answer:
x8+12
x+1
Step-by-step explanation:
Answer:
Step-by-step explanation:
14 + 5t > = 49 (thats a greater then or equal sign)
5t > = 49 - 14
5t > = 35
t > = 35/5
t > = 7 <===
Steps to solve:
3(5x - 8) = 6x + 39
~Distribute left side
15x - 24 = 6x + 39
~Add 24 to both sides
15x = 6x + 63
~Subtract 6x to both sides
9x = 63
~Divide 9 to both sides
x = 7
Best of Luck!
