just use what you know about this stuff
(a+36d)/(a+20d) = (a+55d)/(a+36d)
(a+36d)^2 = (a+55d)(a+20d)
a^2+72ad+1296d^2 = a^2+75ad+1100d^2
3ad = 196d^2
3a = 196d
That is, for any value of n,
a=196n
d=3n
So, there is no unique solution.
If n=1, then a=196 and d=3. The terms are
196+20*3 = 256
196+36*3 = 304
196+55*3 = 361
304/256 = 361/304
You can easily verify that it works for any value of n.
Answer:
The answer is "(5, -6)"
Step-by-step explanation:
Given:
The Pre-image line at point B is: (3, 4)
Solution:
![\ rx-axis \circ \ T2,2 (3,4) \\\\\Rightarrow \ rx-axis \ ( T2,2 (3,4) )\\\\ \Rightarrow \ rx-axis ( 5,6 ) \\\\ \Rightarrow (5, -6)\\](https://tex.z-dn.net/?f=%5C%20rx-axis%20%5Ccirc%20%5C%20%20T2%2C2%20%283%2C4%29%20%5C%5C%5C%5C%5CRightarrow%20%20%5C%20rx-axis%20%5C%20%28%20T2%2C2%20%283%2C4%29%20%29%5C%5C%5C%5C%20%5CRightarrow%20%5C%20rx-axis%20%28%205%2C6%20%20%29%20%5C%5C%5C%5C%20%5CRightarrow%20%20%285%2C%20-6%29%5C%5C)
The coordinates of B point is (5,-6).
Simple, use PEMDAS and then do your simple math and then your answer should be 86922.56604