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Olegator [25]
3 years ago
15

If a fair coin is tossed 6 times, what is the probability, to the nearest

Mathematics
1 answer:
Kipish [7]3 years ago
5 0

Answer:

0

Step-by-step explanation:

the probability of getting 0 heads is not possible as either 1 side has to be a head or a tail

It cannot be none

Therefore...Probability is 0 of getting 0 heads

plz mark as brainliest

thanks

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Answer the following.
kakasveta [241]

Answer:

Step-by-step explanation:

1) y=2sin\frac{x}{2} -2

Altitude = 2

Period = 2pi/(1/2) = 4pi

(since 1/2 is coefficient of x)

Altitude interval = [-4,0]

Domain interval = set of all real numbers

Phase shift = 0

Vertical shift = 2 down

2) y=-4sin(2x+pi/2)-2

Altitude = 4

Period = 2pi/(2) = pi

(since 2 is coefficient of x)

Altitude interval = [-6,2]

Domain interval = set of all real numbers

Phase shift = pi/2

Vertical shift = 2 down

8 0
3 years ago
ABC airlines has had delays on 18 of 126 recent flights . DEF airlines has had delays 13% of the time . Which airline would you
GarryVolchara [31]
ABC airlines because it’s only 18 out of 126 “recent” flights which can only be greater than 13 percent of all of the time so you would have a less percent chance of your flight being delayed.
8 0
3 years ago
$11,000, invested for 9 years at 3% compounded quarterly
12345 [234]
See attachment for your Answer.

8 0
4 years ago
Which table describes the behavior of the graph of f(x) = 2x3 – 26x – 24?
In-s [12.5K]

Answer:

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis

Step-by-step explanation:

f(x)=2x^{3}-26x-24

2x^{3}-26x-24=0

2x^{3}-26x-24=0\\2x^{3}-2x-24x-24=0\\2x(x^{2} -1)-24(x+1)=0\\2x(x+1)(x-1)-24(x+1)=0\\(x+1)(2x^{2} -2x-24)=0\\=> x+1=0 => x_{1}=-1\\

=> 2x^{2} -2x-24=0\\=>2(x^{2} -x-12)=0\\=> x^{2} -x-12=0\\=> x^{2} -4x+3x-12=0\\=> x(x-4)+3(x-4)=0\\=> (x-4)(x+3)=0\\

=> x-4=0\\=> x_{2}=4\\=> x+3=0\\=>x_{3}=-3\\

For x∈ {-∞,-3} y<0, below x-axis

x∈ {-3,-1} y>0, above x-axis

x∈ {-1,4} y<0, below x-axis

x∈ {4,∞} y>0, above x-axis



7 0
4 years ago
Read 2 more answers
Determine whether y2=3x+1 is a function.
bazaltina [42]

Answer: it is not a function

Step-by-step explanation:

Given :

y^{2} = 3x + 1

The first thing is to make y the subject of the formula, that means we will take the square root of both sides

y = \sqrt{3x + 1}

since y =  \sqrt{3x + 1} , the the value of y could be positive or negative.

For example , \sqrt{4} = ± 2 , since -2 x -2 will also give + 4

For y =  \sqrt{3x + 1} to be a function , there must be a unique value for y for each value of x , but this is not the case as y could be positive or negative for a single value of x , so it is not a function.

4 0
3 years ago
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