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3 years ago

Work out the area of the trapezium ABDE.

Mathematics

1 answer:

BartSMP [9]3 years ago

6 0

Answer:

Step-by-step explanation:

Area of a trapezoid = h x (b1+ b2)/2

h= height

b1 and b2 are the bases

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Which ordered pair is a solution of the linear system: x+2y=-8 and

andrew-mc [135]

Answer:

option A

A(-2,-3)

Step-by-step explanation:

make y subject of formula

x+2y=-8

2y=-8-x

y=(-8-x)/2

y=-4-x/2

when x=-2

y=-4-(-2)/2

=-4-(-1)

=-4+1

=-3

(-2,-3) is an ordered pair

5 0

3 years ago

Marco wants to take a taxi cab ride if the cost to ride is 7.00 with the cost per m is 0.25 per mile and mr. o can only spend 30

77julia77 [94]

Each ride has a fixed cost of 7 and a cost that increases proportionally to the distance travelled of 0.25 per mile. Therefore the total cost of the ride is:

$\text{ cost(x)}=0.25\cdot x+7$

Where "x" is the distance in miles. Marco can only spend 30 on his ride, therefore the cost must be less or equal to that value.

$\begin{gathered} \text{ cost(x)}\leq30 \\ 0.25\cdot x+7\leq30 \end{gathered}$

We can solve the linear equation by isolating the "x" variable on the left side.

$\begin{gathered} 0.25\cdot x\leq30-7 \\ 0.25\cdot x\leq23 \\ x\leq\frac{23}{0.25} \\ x\leq92 \end{gathered}$

Marco's travel must be shorter or equal to 92 miles.

6 0

1 year ago

Evaluate 6 C 3 . 18 20 60 120

Novosadov [1.4K]

The answer will be 6 x 5 x 4 / 3 x 2 x 1, 5 x 4 = 20. Hope this helps

5 0

4 years ago

the length of a tangent from a point a at distance 5 cm from the centre of the circle is 4 cm find the radius of the circle

Semenov [28]

The radius of the circle is 3 cm.

Step-by-step explanation:

Refer the attached diagram, the circle with centre O. In that given, AB is tangent given as 4 cm and distance of point from the circle, OA = 5 cm

As AB is tangent, OB (radius of circle) is perpendicular to AB (tangent at any point of circle). Therefore the angle of OBA is 90 degree.

Also, triangle OAB is a right angled triangle (refer attached diagram). By using Pythagoras theorem in right angled triangle,

$(\text {Hypotenuse})^{2}=(\text {Height})^{2}+(\text {Base})^{2}$

$(O A)^{2}=(O B)^{2}+(A B)^{2}$

Substitute the given values in the above expression, we get

$(5)^{2}=(O B)^{2}+(4)^{2}$

$(O B)^{2}=25-16=9$

Taking square root on both side, we get

Radius of the circle, OB = 3 cm

5 0

3 years ago

A PQR = A STU. Find the lengths of the sides PQ, TU, and SU.

Mariana [72]

measure using the object

3 0

3 years ago