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Vitek1552 [10]
3 years ago
15

Match each quadratic equation with its solution set

Mathematics
1 answer:
Sever21 [200]3 years ago
4 0
Hello,
Please, see the attached files.
Thanks.

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Choose the best description for the real number 34 over 3.
harkovskaia [24]

Answer:

The answer is C

Step-by-step explanation:

First of all let's eliminate the answers that do not make sense. For A. numbers are NOT irrational because they are a fraction. Numbers are also not irrational because they are a repeating number. C and D are both correct as fractions and terminating decimals are both rational numbers.

34/3≈11.33333333

By using a certain formula you can convert repeating decimals to a fraction. But most people know that .3333333 is 1/3. This gives us 11 1/3 as our answer. So what does it match? It is not a terminating decimal. It repeats but can be written as a fraction. Therefore our answer is C) Rational, because it is a fraction.

7 0
3 years ago
Can someone please help me on this I’m not sure if what I is the correct answer someone help
tia_tia [17]

Answer: you got it right, it is the one that is blue highlighted.

6 0
4 years ago
How to estimate then find the difference
Mademuasel [1]

Answer:

Step-by-step explanation:

6 0
3 years ago
The frequency, f, in Hz, at which a simple pendulum rocks back and forth is given by 1 , 2 g f π l = where g is the strength of
Monica [59]

Answer:

a. 0.9 Hz b. 0.37 Hz

Step-by-step explanation:

The frequency of the simple pendulum f = (1/2π)√g/l where g = acceleration due to gravity and l = length of pendulum

a. Find the frequency of a pendulum whose length is 1 foot and where the gravitational field is approximately 32 ft/s2

To find f on Earth, g = 32 ft/s² and l = 1 ft

So, f =  (1/2π)√(g/l)

f = (1/2π)√(32 ft/s²/1 ft)

f = (1/2π)√(32/s²)

f = (1/2π)(5.66 Hz)

f = 0.9 Hz

b. The strength of the gravitational field on the moon is about 1/6 as strong as on Earth.. Find the frequency of the same pendulum on the moon.

On the moon when acceleration due to gravity g' = g/6,

f =  (1/2π)√(g'/l)

f =  (1/2π)√(g/6l)

f = (1/2π)√[32 ft/s²/(6 × 1 ft)]

f = (1/2π)√(32/s²)/√6

f = (1/2π)(5.66 Hz)/√6

f = 0.9/√6 Hz

f = 0.37 Hz

3 0
3 years ago
Find the unknow measures of y and x.​
Yanka [14]

9514 1404 393

Answer:

  x = 2 m

  y = 30°

Step-by-step explanation:

The side lengths of ΔDEF are 3/9 = 1/3 of those of ΔABC.

  x = DF = 1/3(AB) = (1/3)(6 m)

  x = 2 m

__

Angle measures of ΔDEF are the same as those of the corresponding angles of ΔABC.

  y = ∠B = ∠E = 30°

  y = 30°

8 0
3 years ago
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