3 years ago

Match each quadratic equation with its solution set

Mathematics

1 answer:

Sever21 [200]3 years ago

4 0

Hello,
Please, see the attached files.
Thanks.

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Evaluate: 20 Σ 4(8/9)^n-1 = [?] 1 Round to the nearest hundredth.

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Step-by-step explanation:

Geometric sequence

General form of a geometric sequence: $a_n=ar^{n-1}$

(where a is the first term and r is the common ratio)

Given:

$\displaystyle \sum^{20}_{n=1} 4 \left(\dfrac{8}{9}\right)^{n-1}$

Therefore:

a = 4
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Sum of the first n terms of a geometric series:

$S_n=\dfrac{a(1-r^n)}{1-r}$

To find the sum of the first 20 terms, substitute the found values of a and r, together with n = 20, into the formula:

$\implies S_{20}=\dfrac{4\left(1-\left(\frac{8}{9}\right)^{20}\right)}{1-\left(\frac{8}{9}\right)}$

$\implies S_{20}=32.58609013...$

$\implies S_{20}=32.59\:\: \sf (nearest\:hundredth)$

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