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likoan [24]
3 years ago
11

The larger of two numbers is 7 times the smaller number. 3 times the larger number is 7 more than 4 times the smaller number. Fi

nd the numbers. Please answer!!!!!!!!!! I BEG!!!!!
Mathematics
1 answer:
zhenek [66]3 years ago
5 0
So the larger number is x, and the smaller number is y
7y=x
3x=7+4y

(So plug in the 7y=x information into the second equation)

3(7y)=7+4y
21y=7+4y
17y=7
y=7/17
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A man is driving to pick his daughter from school. He waits for his daughter to be done, then he drives back home.

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4 years ago
Sheila purchased ski equipment for $513 using a six-month deferred payment plan. The interest rate after the introductory period
klemol [59]

$65 * 6 = $390 total monthly payments made

The downpayment made is $125, so the total balance at the end is:

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balance = - $2

 

<span>There is an excess of 2 dollars at the end.</span>

4 0
3 years ago
What is the percentage of cacao in hot chocolate which is made of 480 grams of milk and 20 grams of cacao?
galina1969 [7]

Given that the hot chocolate is made of 480 grams of milk and 20 grams of cacao.

We need to determine the percentage of cacao in hot chocolate.

<u>The percentage of cacao:</u>

The total grams of hot chocolate can be determined by adding the total grams of milk and the total grams of cacao.

Total grams of hot chocolate = Grams of Milk + Grams of cacao

Total grams of hot chocolate = 480 + 20 = 500 grams.

Thus, the total grams of hot chocolate is 500 grams.

Now, we shall find the percentage of cacao.

The percentage of cacao is given by

\frac{100}{500}\times 20

Simplifying, the values, we get,

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6 0
3 years ago
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5 0
3 years ago
Read 2 more answers
A polynomial function has a zero at 4 (multiplicity 3) and 0 (multiplicity 1). Write a function in standard form that can repres
VLD [36.1K]

Answer:

(x^4) - 64x

Step-by-step explanation:

zeros at 4 and 0 are the roots so can be factor as x*(x-4) and the multiplicity tels to what power you have to raise those factors

x^{1} *(x-4)^{3} becuase multiplicity of 1 for root at 0, and multiplicity of 3 at root 4

now to write this in standard form

x*(x-4)^{3} = \\x*(x-4)(x^{2} +4x+16)= \\(x^{2} -4x)(x^{2} +4x+16) = \\x^{4} +4x^{3} +16x^{2} -4x^{3} -16x^{2} -64x = \\x^{4} -64x

8 0
3 years ago
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