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Answer:</h3>
0.387 J/g°C
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Explanation:</h3>
- To calculate the amount of heat absorbed or released by a substance we need to know its mass, change in temperature and its specific heat capacity.
- Then to get quantity of heat absorbed or lost we multiply mass by specific heat capacity and change in temperature.
- That is, Q = mcΔT
in our question we are given;
Mass of copper, m as 95.4 g
Initial temperature = 25 °C
Final temperature = 48 °C
Thus, change in temperature, ΔT = 23°C
Quantity of heat absorbed, Q as 849 J
We are required to calculate the specific heat capacity of copper
Rearranging the formula we get
c = Q ÷ mΔT
Therefore,
Specific heat capacity, c = 849 J ÷ (95.4 g × 23°C)
= 0.3869 J/g°C
= 0.387 J/g°C
Therefore, the specific heat capacity of copper is 0.387 J/g°C
Answer: The Answers are: 0.31g & 0.011mol & 3.34g & 0.016mol.
Explanation: Solved in the attached picture.
False. An ion has an imbalanced number of protons and electrons.
Lithium is one of element of group 1 of periodic table.
Lithium has the smallest radius than as compared to the other elements, thus the density of the alkali metal is also less.
Lithium when added to water it floats, because of lower density. It eventually fizzes and becomes smaller.
The reaction on lithium and water is:
2Li + 2H₂O --> 2LiOH + H₂ (g)
The hydrogen gas which is liberated is highly flammable.
Thus, lithium salts are insoluble in water.
Density is defined as the mass of a substance per unit volume.
Density = Mass ÷ Volume.
To know more about Alkali metals, refer to this link:
brainly.com/question/5063184
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Answer:
10 moles of water are produced,
Explanation:
Given data:
Moles of H = 10 mol
Moles of O = 6 mol
Water obtained = ?
Solution:
Balance chemical equation:
2H₂ + O₂ → 2H₂O
Now we will compare the moles of H₂ and O₂ with water from balance chemical equation.
H₂ : H₂O
2 : 2
10 : 10
O₂ : H₂O
1 : 2
6 : 2×6 = 12
Number of moles of water produced by hydrogen are less so hydrogen will be limiting reactant and it will limit the yield of water thus, 10 moles of water are produced.
