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luda_lava [24]
3 years ago
15

A 7.0 L sample of methane gas is collected at 50.0°C. Predict the volume of the sample at 0°C.

Chemistry
1 answer:
gizmo_the_mogwai [7]3 years ago
3 0

Answer:

V₂ = 5.92 L

Explanation:

Given data:

Initial volume of methane = 7.0 L

Initial temperature = 50.0°C

Final temperature = 0°C

Final volume = ?

Solution:

Initial temperature = 50.0°C (50+273 = 323 K)

Final temperature = 0°C (0+273 = 273 K)

According to this law, The volume of given amount of a gas is directly proportional to its temperature at constant number of moles and pressure.

Mathematical expression:

V₁/T₁ = V₂/T₂

V₁ = Initial volume

T₁ = Initial temperature

V₂ = Final volume  

T₂ = Final temperature

Now we will put the values in formula.

V₁/T₁ = V₂/T₂

V₂ = V₁T₂/T₁  

V₂ = 7 L × 273 K / 323 k

V₂ = 1911 L.K / 323 K

V₂ = 5.92 L

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The nonmetals include which of the following groups? Use the periodic table to answer the question.
strojnjashka [21]

Answer:

halogen

Explanation:

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7 0
3 years ago
A gaseous system undergoes a change in temperature and volume. What is the entropy change for a particle in this system if the f
deff fn [24]

Explanation:

Entropy means the amount of randomness present within the molecules of the body of a substance.

Relation between entropy and microstate is as follows.

           S = K_{b} \times ln \Omega

where,      S = entropy

             K_{b} = Boltzmann constant

             \Omega = number of microstates

This equation only holds good when the system is neither losing or gaining energy. And, in the given situation we assume that the system is neither gaining or losing energy.

Also, let us assume that \Omega = 1, and \Omega' = 0.833

Therefore, change in entropy will be calculated as follows.

     \Delta S = K_{b} \times ln \Omega' - K_{b} \times ln \Omega

                 = 1.38 \times 10^{-23} \times ln(0.833) - 1.38 \times 10^{-23} \times \times ln(1)

                 = 1.38 \times 10^{-23} \times (-0.182)

                 = -0.251 \times 10^{-23}

or,             = -2.51 \times 10^{-24}

Thus, we can conclude that the entropy change for a particle in the given system is -2.51 \times 10^{-24} J/K particle.

8 0
3 years ago
The nucleus of a lead atom has a charge of 82 protons what are the drection and magnitude
KATRIN_1 [288]

Answer:

left

Explanation:

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Determine the total kilojoules in two tablespoons of crunchy peanut butter that contains 6 g of carbohydrate, 11 g of fat, and 9
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Answer:

  665 kJ

Explanation:

We assume that carbohydrates and protein each have 4 kilocalories per gram, and that fat has 9 kilocalories per gram. Then the number of kilocalories in the peanut butter is ...

  4(6 +9) +9(11) = 159 . . . . kilocalories

Each kilocalorie translates to 4.184 kilojoules, so the total is ...

  (159 kCal)(4.184 kJ/kCal) = 665.256 kJ

2 Tbsp of crunchy peanut butter contains about 665 kJ of energy.

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3 years ago
State and explain the relative change in the pH and in the buffer-component concentration ratio, [NaA]/[HA], for each of the fol
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What is Acid?

Any material that when dissolved in water has an acidic taste, can alter the colour of some indicators (such as reddening blue litmus paper), can react with some metals (such as iron) to release hydrogen, can combine with bases to produce salts, and can accelerate some chemical reactions (acid catalysis). Acids are examples of organic chemicals that belong to the carboxylic acid, sulfonic acid, and phenol groups as well as the inorganic substances known as the mineral acids, such as sulfuric, nitric, hydrochloric, and phosphoric acids. These chemicals contain one or more hydrogen atoms, which are discharged as positively charged hydrogen ions when they are in solution.

To learn more about Acid, visit:

brainly.com/question/14072179

#SPJ4

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2 years ago
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