To find the x-intercept, substitute in 0 for y and solve for x. To find the y-intercept, substitute in 0 for x and solve for y.
x-intercept - (3,0)
y-intercept - (0,12)
Slope: -4
Y-intercept: 12
Answer:
A: 0
Step-by-step explanation:
Important to remember - total displacement is the direct distance between the start and finish points, and isn't always equal to the total distance travelled.
In the case of the table above, the hiker travels the same distance in opposite directions, which actually means they cancel each other out! Traveling 4 km to the west, then 4 km to east means you end up in the same spot, right? So your total displacement is 0! (or 4 - 4, which equals 0). Same happens with the north-south hikes - the hiker ends up in the same spot, as the displacement is equal to 6 - 6 = 0.
So, the total displacement of the hiker is 0. (Even though the hiker travelled 20 km!)
You are asked to do this problem by graphing, which would be hard to do over the Internet unless you can do your drawing on paper and share the resulting image by uploading it to Brainly.
If this were homework or a test, you'd get full credit only if you follow the directions given.
If <span>The points(0,2) and (4,-10) lie on the same line, their slope is m = (2+10)/(-4), or m =-3. Thus, the equation of this line is y-2 = -3x, or y = -3x + 2.
If </span><span>points (-5,-3) and (2,11) lie on another line, the slope of this line is:
m = 14/7 = 2. Thus, the equation of the line is y-11 = 2(x-2), or y = 11+2x -4, or y = 2x + 7.
Where do the 2 lines intersect? Set the 2 equations equal to one another and solve for x:
</span>y = -3x + 2 = y = 2x + 7. Then 5x = 5, and x=1.
Subst. 1 for x in y = 2x + 7, we get y = 2(1) + 7 = 9.
That results in the point of intersection (2,9).
Doing this problem by graphing, on a calculator, produces a different result: (-1,5), which matches D.
I'd suggest you find and graph both lines yourself to verify this. If you want, see whether you can find the mistake in my calculations.
That is height
h=16t^2+16t+480
when h=0 is when it hits the water
0=16t^2+16t+480
undistribbute 16 for ease
0=16(t^2+t+30)
16*0=0 so assume
t^2+t+30=0
factor
(t+6)(t-5)=0
set to zero
t+6=0
minus 6
t=-6
false, since you cannot have negative time
t-5=0
add 5
t=5
at t=5 she hits the water
5 seconds
<span>(18<span>t<span><span>^2</span><span> </span></span></span>+ 9<span>t^<span><span>2</span><span></span></span></span>) + (−7t −3t) + 20
</span><span><span>27<span>t<span><span>^2</span><span> </span></span></span>− 10t + 20</span><span>
</span></span><span>
</span>