Tami thought that the perimiter is length plus width, which gave her 100. The actual width is 20
Step-by-step explanation:
a)
total no. of pupils is not more than 24
therefore first equation is
(x+y) ≤ 24. ....(1)
No. of girls exceeding the no. of boys by atleast 4
(y-x) ≥ 4. .....(2)
b) Now Liza chooses 8 boys
Maximum no. of girls = ?
Using first inequality
y+8= 24 ( maximum value of less than or equal to function is equal to itself)
Therefore,
y= 24-8
=16
Minimum no. of girls = ?
Using second inequality
y-8 =4 (minimum value of greater than or equal to function is equal to itself)
Therefore,
y= 4+8
y=12
Answer:
a) 2linear inequalities
(x+y) ≤ 24
(y-x) ≥ 4
b) Max no. of girls = 16
Min no. of girls = 12
Hope it helps...
The biggest common factor number is the GCF number. So the greatest common factor 9 and 14 is 1.
Answer:
Q1: 12.5
Q3: 16
IQR: 3.5
Step-by-step explanation:
Mean : 14.25
Median : 13.5
Mode : 13, 12
Range: 6
Minimum :12
Maximum: 18
Count n: 8
Sum: 114
Quartiles Quartiles:
Q1 --> 12.5
Q2 --> 13.5
Q3 --> 16
Interquartile
Range IQR: 3.5
Outliers: none
Answer:
the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
Step-by-step explanation:
From the five randomly selected students ; 160, 175, 163, 149, 153
mean average of the students = 160+175+163+149+153/5
= mean = x-bar = 800/5
mean x-bar = 160
from probability distribution, P(x-bar > 160) = P[ x-bar - miu / SD > 160 -150.8 /3.94]
P( Z>2.34) = from normal Z-distribution table
= 0.0096419
= 0.0096
hence the probability that five randomly selected students will have a mean score that is greater than the mean achieved by the students = 0.0096
where SD = standard deviation = 3.94 and Miu = 150.8
